sin(%pi^2) is not zero. That is correct. A numerical approximation is
(%i17) sin(%pi^2),numer;
(%o17) -0.43030121700009
Closing this report support request.
Dieter Kaiser
How does Maxima distinguish between sin^2(%pi) and sin(%pi^2)?
sin(%pi)=0 and then sin^2(%pi)=0, but sin(%pi^2) is not zero.
sin(%pi^2) is not zero. That is correct. A numerical approximation is
(%i17) sin(%pi^2),numer;
(%o17) -0.43030121700009
Closing this report support request.
Dieter Kaiser
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