Re: [Maxima-discuss] elementary solve() problem

[richard c. <rp...@cl...>]

Terrific. Thank you, Barton.
And needless to say, apologies for the accidental repetition in the 
first 6 lines of my example...

rc

On 2025-11-13 11:23, Barton Willis wrote:
> Try setting the option variable solveradcan to true before solving:
> 
>  (%i1) solveradcan : true$
> 
>  (%i2) solve(n*10^(n-1)=2*n*5^(n-1),n);
>  (%o2) [n=0,n=2]
> 
>  Alternatively, apply radcan before solving:
> 
>  (%i1) radcan(n*10^(n-1)=2*n*5^(n-1));
>  (%o1) 2^(n-1)*5^(n-1)*n=2*5^(n-1)*n
> 
>  (%i2) solve(%,n);
>  (%o2) [n=0,n=2]
> 
>  For a list of additional option variables (and a bunch of other
> stuff) that affect how solve works, try
> 
>  (%i3) apropos (solve);
>  
> (%o3) [desolve,funcsolve,globalsolve,linsolve,linsolve_by_lu,linsolve_params,linsolvewarn,solve,solve_congruences,solvedecomposes,solveexplicit,solvefactors,
> 
>  Solvenullwarn,solveradcan,solvetrigwarn,tmlinsolve,to_poly_solve]
> 
>  Thanks for your interest in Maxima! If you have more questions, feel
> free to ask.
> 
>  --Barton
> 
> -------------------------
> 
> From: richard christian <rp...@cl...>
> Sent: Thursday, November 13, 2025 3:57 AM
> To: max...@li...
> <max...@li...>
> Subject: [Maxima-discuss] elementary solve() problem
> 
> Caution: Non-NU Email
> 
> Apologies for this very novice question, but what am I doing wrong
> here?
> Why isn't Maxima giving n=2?
> 
> (%i18)  s: t**n;
> (s)     t^n
> (%i19)  diff(s,t);
> (%o19)  n*t^(n-1)
> (%i20)  s: t**n;
> (s)     t^n
> (%i21)  diff(s,t);
> (%o21)  n*t^(n-1)
> (%i23)  ev(%,t=10) = 2*ev(%,t=5);
> (%o23)  n*10^(n-1)=2*n*5^(n-1)
> (%i24)  solve(%,n);
> (%o24)  [n=0,10^(n-1)=2*5^(n-1)]
> 
> Many thanks, Richard
> 
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