Re: [Maxima-discuss] Strange semantics when a macro calls other macro

[Stavros M. <mac...@gm...>]

This seems like an awfully convoluted way of proceeding.
I would strongly recommend trying to do it without macros at all.
But maybe I don't understand what you're trying to do.

On Thu, Jul 11, 2024 at 4:32 PM Eduardo Ochs <edu...@gm...> wrote:

> Hi list,
>
> can anyone help me to understand what is happening in the program
> below?
>
>   mkmatrix0(xs, ys, expr) :=
>     buildq([xs,ys,expr],
>       apply(matrix,
>             makelist(makelist(expr, splice(xs)),
>                      splice(ys))))$
>
>   mkmatrix (xs, ys, expr) ::= mkmatrix0 (xs, ys, expr)$
>
>   Dx : x - x0;
>   Dy : y - y0;
>   [x0,y0] : [3,2];
>   mkmatrix ([x,0,x0+1], [y,y0+1,0,-1], [x,y]);
>   mkmatrix ([x,0,x0+1], [y,y0+1,0,-1], ev([Dx,Dy]));
>   a : mkmatrix ([x,x0-1,x0+1], [y,y0+1,y0-1,-1], [x,y]);
>   b : mkmatrix ([x,x0-1,x0+1], [y,y0+1,y0-1,-1], ev([Dx,Dy]));
>
>   aroundx0y0(expr) ::= mkmatrix ([x,x0-1,x0+1], [y,y0+1,y0-1,-1], expr)$
>
>   c : aroundx0y0([x,y]);
>   d : aroundx0y0(ev([Dx,Dy]));
>
> I was expecting that a and c would return the same matrix, and b and d
> would return the same (other) matrix, but no... in the lines that
> calculate a and b the symbols x and y are become bound variables
> inside the two "makelist"s, but in the lines that calculate c and d
> the x and the y don't change...
>
> Thanks in advance!
>   [[]], Eduardo...
>
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