Re: [Maxima-discuss] Integral of equation

[Daniel V. <dan...@ya...>]

 Richard,
The two atvalue commands where there by mistake. The moment I realized thatone of the commands blocks the substitution, I decided to leave it in the example.
The integrate command does refer to the atvalue command. Using Leo's solution, if Iput atvalue(diff(y(x),x),x=a,y\'_a) before the integrate, it will use the value y\'_a.
Leo,
Thank you for your solution, it works very well.
Daniel Volinski
    En martes, 17 de octubre de 2023, 21:32:32 GMT+3, Leo Butler <leo...@um...> escribió:  
 
 On Tue, Oct 17 2023, Daniel Volinski via Maxima-discuss <max...@li...> wrote:

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> Hi All,
> I have the following code:
> declare([a,b,y_a,y_b],constant)$
>
> atvalue(y(x),x=a,y_a)$atvalue(y(x),x=b,y_b)$
> assume(a<x,x<b)$
>
> Eq0:'diff(y(x),x,2)=u(x); => 'diff(y(x),x,2) = u(x)
> Eq1:integrate(Eq0,x,a,x); => 'diff(y(x),x,1)-'diff(y(a),a,1) = 'integrate(u(x),x,a,x)

A bit of part-hacking will give you what you want:

subst(part(Eq1,1,2,1)='at(diff(y(x),x,1),x=a),Eq1);

----

matchdeclare + tellsimpafter will also do the substitution
automatically:

display2d:false $
matchdeclare(CCC,constantp,AAA,true);
block([simp:false],
        tellsimpafter('diff(AAA,CCC,1),
        at('diff(subst([CCC=x],AAA),x,1),x=CCC)));
        
declare(a,constant);        
Eq0:'diff(y(x),x,2)=u(x);
integrate(Eq0,x,a,x);


#+begin_example
(%i1) display2d:false $
(%i2) matchdeclare(CCC,constantp,AAA,true);
(%o2) done
(%i3) block([simp:false],
        tellsimpafter('diff(AAA,CCC,1),
        at('diff(subst([CCC=x],AAA),x,1),x=CCC)));
(%o3) [derivativerule1,simpderiv]
(%i4) declare(a,constant);        
(%o4) done
(%i5) Eq0:'diff(y(x),x,2)=u(x);
(%o5) 'diff(y(x),x,2) = u(x)
(%i6) integrate(Eq0,x,a,x);
(%o6) 'diff(y(x),x,1)-%at('diff(y(x),x,1),x = a) = 'integrate(u(x),x,a,x)
#+end_example

>
> Eq2:subst(['diff(y(a),a,1)=y\'(a)],Eq1); => 'diff(y(x),x,1)-'diff(y(a),a,1) = 'integrate(u(x),x,a,x)

If you evaluate 'diff(y(a),a,1), you will see that Maxima evaluates that
to 0.

Leo

>
> The first error is in Eq1, the result contains 'diff(y(a),a,1) which
> makes no sense.The second error is in Eq2, I'm unable to do the
> substitution of the error.
> If I delete atvalue(y(x),x=a,y_a)$ and run all again the substitution
> is OK.If I do the integration with limits a and b, then both terms of
> the left-hand side are incorrect.
> Is there any way to fix it?Thanks,
> Daniel Volinski
>
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