## [Maxima-bugs] [ maxima-Bugs-738848 ] Poverseries error for 1/(1-t)^2

 [Maxima-bugs] [ maxima-Bugs-738848 ] Poverseries error for 1/(1-t)^2 From: SourceForge.net - 2003-05-17 18:32:39 ```Bugs item #738848, was opened at 2003-05-16 09:15 Message generated for change (Comment added) made by nobody You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=738848&group_id=4933 Category: Share Libraries Group: Fix for 5.9.0 Status: Open Resolution: None Priority: 5 Submitted By: Nobody/Anonymous (nobody) Assigned to: Nobody/Anonymous (nobody) Summary: Poverseries error for 1/(1-t)^2 Initial Comment: It seems powerseries(1(a-b*t)^n, t, 0) produces an error for n=2, but is correct for n=1,3,4: (C1) POWERSERIES(1/(a-b*t)^2, t, 0); INF ==== \ I1 - I1 - 2 I1 (D1) > a b (I1 + 1) t / ==== I1 = 0 [I believe that powers of a and b above have opposite signs]. ---------------------------------------------------------------------- Comment By: Nobody/Anonymous (nobody) Date: 2003-05-17 11:32 Message: Logged In: NO (C1) verbose:true; (D1) TRUE (C2) POWERSERIES(1/(a-b*t)^2, t, 0); In the first simplification we have returned: 1 -------------------- 2 2 2 b t - 2 a b t + a trying to do a rational function expansion of 1 -------------------- 2 2 2 b t - 2 a b t + a Using a special rule for expressions of form M - N (A + C VAR ) Here we have [N = 2, A = - a, C = b, M = 1] INF ==== \ I1 - I1 - 2 I1 (D2) > a b (I1 + 1) t / ==== I1 = 0 (C3) ---------------------------------------------------------------------- You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=738848&group_id=4933 ```

 [Maxima-bugs] [ maxima-Bugs-738848 ] Poverseries error for 1/(1-t)^2 From: SourceForge.net - 2003-05-16 16:15:53 ```Bugs item #738848, was opened at 2003-05-16 09:15 Message generated for change (Tracker Item Submitted) made by Item Submitter You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=738848&group_id=4933 Category: Share Libraries Group: Fix for 5.9.0 Status: Open Resolution: None Priority: 5 Submitted By: Nobody/Anonymous (nobody) Assigned to: Nobody/Anonymous (nobody) Summary: Poverseries error for 1/(1-t)^2 Initial Comment: It seems powerseries(1(a-b*t)^n, t, 0) produces an error for n=2, but is correct for n=1,3,4: (C1) POWERSERIES(1/(a-b*t)^2, t, 0); INF ==== \ I1 - I1 - 2 I1 (D1) > a b (I1 + 1) t / ==== I1 = 0 [I believe that powers of a and b above have opposite signs]. ---------------------------------------------------------------------- You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=738848&group_id=4933 ```
 [Maxima-bugs] [ maxima-Bugs-738848 ] Poverseries error for 1/(1-t)^2 From: SourceForge.net - 2003-05-17 18:32:39 ```Bugs item #738848, was opened at 2003-05-16 09:15 Message generated for change (Comment added) made by nobody You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=738848&group_id=4933 Category: Share Libraries Group: Fix for 5.9.0 Status: Open Resolution: None Priority: 5 Submitted By: Nobody/Anonymous (nobody) Assigned to: Nobody/Anonymous (nobody) Summary: Poverseries error for 1/(1-t)^2 Initial Comment: It seems powerseries(1(a-b*t)^n, t, 0) produces an error for n=2, but is correct for n=1,3,4: (C1) POWERSERIES(1/(a-b*t)^2, t, 0); INF ==== \ I1 - I1 - 2 I1 (D1) > a b (I1 + 1) t / ==== I1 = 0 [I believe that powers of a and b above have opposite signs]. ---------------------------------------------------------------------- Comment By: Nobody/Anonymous (nobody) Date: 2003-05-17 11:32 Message: Logged In: NO (C1) verbose:true; (D1) TRUE (C2) POWERSERIES(1/(a-b*t)^2, t, 0); In the first simplification we have returned: 1 -------------------- 2 2 2 b t - 2 a b t + a trying to do a rational function expansion of 1 -------------------- 2 2 2 b t - 2 a b t + a Using a special rule for expressions of form M - N (A + C VAR ) Here we have [N = 2, A = - a, C = b, M = 1] INF ==== \ I1 - I1 - 2 I1 (D2) > a b (I1 + 1) t / ==== I1 = 0 (C3) ---------------------------------------------------------------------- You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=738848&group_id=4933 ```
 [Maxima-bugs] [ maxima-Bugs-738848 ] Poverseries error for 1/(1-t)^2 From: SourceForge.net - 2003-05-19 08:32:06 ```Bugs item #738848, was opened at 2003-05-16 16:15 Message generated for change (Comment added) made by kratt5 You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=738848&group_id=4933 Category: Share Libraries Group: Fix for 5.9.0 Status: Open Resolution: None Priority: 5 Submitted By: Nobody/Anonymous (nobody) Assigned to: Nobody/Anonymous (nobody) Summary: Poverseries error for 1/(1-t)^2 Initial Comment: It seems powerseries(1(a-b*t)^n, t, 0) produces an error for n=2, but is correct for n=1,3,4: (C1) POWERSERIES(1/(a-b*t)^2, t, 0); INF ==== \ I1 - I1 - 2 I1 (D1) > a b (I1 + 1) t / ==== I1 = 0 [I believe that powers of a and b above have opposite signs]. ---------------------------------------------------------------------- Comment By: Martin Rubey (kratt5) Date: 2003-05-19 08:32 Message: Logged In: YES user_id=651552 This is fixed with the fix for [727542] powerseries wrong/fix Martin (please, somebody merge it into cvs, it is IMPORTANT!) ---------------------------------------------------------------------- Comment By: Nobody/Anonymous (nobody) Date: 2003-05-17 18:32 Message: Logged In: NO (C1) verbose:true; (D1) TRUE (C2) POWERSERIES(1/(a-b*t)^2, t, 0); In the first simplification we have returned: 1 -------------------- 2 2 2 b t - 2 a b t + a trying to do a rational function expansion of 1 -------------------- 2 2 2 b t - 2 a b t + a Using a special rule for expressions of form M - N (A + C VAR ) Here we have [N = 2, A = - a, C = b, M = 1] INF ==== \ I1 - I1 - 2 I1 (D2) > a b (I1 + 1) t / ==== I1 = 0 (C3) ---------------------------------------------------------------------- You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=738848&group_id=4933 ```
 [Maxima-bugs] [ maxima-Bugs-738848 ] Poverseries error for 1/(1-t)^2 From: SourceForge.net - 2003-05-28 16:41:10 ```Bugs item #738848, was opened at 2003-05-16 12:15 Message generated for change (Comment added) made by rtoy You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=738848&group_id=4933 Category: Share Libraries Group: Fix for 5.9.0 >Status: Closed >Resolution: Duplicate Priority: 5 Submitted By: Nobody/Anonymous (nobody) Assigned to: Nobody/Anonymous (nobody) Summary: Poverseries error for 1/(1-t)^2 Initial Comment: It seems powerseries(1(a-b*t)^n, t, 0) produces an error for n=2, but is correct for n=1,3,4: (C1) POWERSERIES(1/(a-b*t)^2, t, 0); INF ==== \ I1 - I1 - 2 I1 (D1) > a b (I1 + 1) t / ==== I1 = 0 [I believe that powers of a and b above have opposite signs]. ---------------------------------------------------------------------- >Comment By: Raymond Toy (rtoy) Date: 2003-05-28 12:41 Message: Logged In: YES user_id=28849 Bug marked as duplicate. I'll apply your patch for bug 727542. ---------------------------------------------------------------------- Comment By: Martin Rubey (kratt5) Date: 2003-05-19 04:32 Message: Logged In: YES user_id=651552 This is fixed with the fix for [727542] powerseries wrong/fix Martin (please, somebody merge it into cvs, it is IMPORTANT!) ---------------------------------------------------------------------- Comment By: Nobody/Anonymous (nobody) Date: 2003-05-17 14:32 Message: Logged In: NO (C1) verbose:true; (D1) TRUE (C2) POWERSERIES(1/(a-b*t)^2, t, 0); In the first simplification we have returned: 1 -------------------- 2 2 2 b t - 2 a b t + a trying to do a rational function expansion of 1 -------------------- 2 2 2 b t - 2 a b t + a Using a special rule for expressions of form M - N (A + C VAR ) Here we have [N = 2, A = - a, C = b, M = 1] INF ==== \ I1 - I1 - 2 I1 (D2) > a b (I1 + 1) t / ==== I1 = 0 (C3) ---------------------------------------------------------------------- You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=738848&group_id=4933 ```