Re: [Maxima-discuss] a^b to exp(b*log(a))

[Gunter K. <gu...@pe...>]

In theory it is. But if I don't substitute the operator from within
maxima making the equation use f(a,b) requires a handful of regexps =>
this time the subst() approach is easier.

Thanks a lot,
and

Kind regards,

 Gunter.

On 21.11.2017 15:35, Jaime Villate wrote:
> On 21-11-2017 13:55, Gunter Königsmann wrote:
>> Some programming language don't provide an a^b command, but only exp(x)
>> and log(x).
>>
>> Does maxima provide a function that converts expressions between these
>> two forms?
> 
> Is  f(a,b):=exp(b*log(a)) enough?
> 
> Jaime
>