From: Richard F. <fa...@be...> - 2016-01-14 19:36:43
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On 1/14/2016 11:24 AM, Barton Willis wrote: > > > > So for example limit(sqrt(x),x,0,minus)=>0, though sqrt(x) is not > defined over the negative reals and so I suppose in principle this > should be UND. > > > > Sorry, in my other post on this, I missed the limit from the left. The > function x in [0,\inf) --> sqrt(x) does not have a limit from the left > toward zero. This is because 0 isn't a limit point of (-inf,0] > intersect [0, inf). > > > --Barton > > > I think we have to consider that Maxima is perfectly happy to evaluate sqrt(x) for negative reals, and so we could convert the limit(sqrt(x),x,0,minus) to limit(sqrt(-x),x,0,plus) to limit(%i*sqrt(x),0,plus) to %i* limit(sqrt(x),x,0,plus) to %i* 0 to 0. This seems different in nature from limit(log(x),x,0,minus) which ends up with %i*%pi hanging out... |