Re: [Maxima-discuss] weird behavior of apply

[Stavros M. (Σ. Μ. <mac...@al...>]

You are calling dy(y=0). I think you want to call dy(0).

On Mon, Sep 29, 2014 at 1:30 PM, Dimiter Prodanov <dim...@gm...>
wrote:

> Hello,
>
> I define a function
>
> dy(y):=if y#0 and y#0.0 then  1/(2*y)   else 'nan;
>
> Then I wanted to substitute it's first argument by a value. The idea is to
> use pass a function having a variable number of arguments as a method
> parameter and then to evaluate it only on certain arguments.
>
>
> I stumbled on the following weird behavior:
>
> apply(dy, [y=0]);
> expt: undefined: 0 to a negative exponent.
>  -- an error.
>
> also here
>
> at(dy(y),[y=0]);
>
> expt: undefined: 0 to a negative exponent.
>  -- an error.
>
> while  dy(0) correctly evaluates to 'nan
>
> best regards,
>
> Dimiter
>
>
>
>
>
>
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