## [Maxima-bugs] [ maxima-Bugs-1430843 ] integrate(x/(1-x^2), x) and integrate(x/(x^2-1), x)

 [Maxima-bugs] [ maxima-Bugs-1430843 ] integrate(x/(1-x^2), x) and integrate(x/(x^2-1), x) From: SourceForge.net - 2011-02-12 18:49:12 ```Bugs item #1430843, was opened at 2006-02-13 13:10 Message generated for change (Settings changed) made by dgildea You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=1430843&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Lisp Core - Integration Group: None >Status: Pending Resolution: None Priority: 5 Private: No Submitted By: Raymond Toy (rtoy) Assigned to: Nobody/Anonymous (nobody) Summary: integrate(x/(1-x^2),x) and integrate(x/(x^2-1),x) Initial Comment: integrate(x/(1-x^2),x) and integrate(x/(x^2-1),x) don't ask if x < 1 or x > 1. Because of this we get two different results, when they should be equivalent, depending on the range of integration. ---------------------------------------------------------------------- Comment By: Dan Gildea (dgildea) Date: 2011-01-24 16:25 Message: (%i2) integrate(x/(1-x^2),x); (%o2) -log(1-x^2)/2 (%i3) integrate(x/(x^2-1),x); (%o3) log(x^2-1)/2 The two results are equivalent except for their sign, and a constant term of log(-1). I don't understand the problem. ---------------------------------------------------------------------- You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=1430843&group_id=4933 ```

 [Maxima-bugs] [ maxima-Bugs-1430843 ] integrate(x/(1-x^2), x) and integrate(x/(x^2-1), x) From: SourceForge.net - 2011-01-24 21:25:02 ```Bugs item #1430843, was opened at 2006-02-13 13:10 Message generated for change (Comment added) made by dgildea You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=1430843&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Lisp Core - Integration Group: None Status: Open Resolution: None Priority: 5 Private: No Submitted By: Raymond Toy (rtoy) Assigned to: Nobody/Anonymous (nobody) Summary: integrate(x/(1-x^2),x) and integrate(x/(x^2-1),x) Initial Comment: integrate(x/(1-x^2),x) and integrate(x/(x^2-1),x) don't ask if x < 1 or x > 1. Because of this we get two different results, when they should be equivalent, depending on the range of integration. ---------------------------------------------------------------------- >Comment By: Dan Gildea (dgildea) Date: 2011-01-24 16:25 Message: (%i2) integrate(x/(1-x^2),x); (%o2) -log(1-x^2)/2 (%i3) integrate(x/(x^2-1),x); (%o3) log(x^2-1)/2 The two results are equivalent except for their sign, and a constant term of log(-1). I don't understand the problem. ---------------------------------------------------------------------- You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=1430843&group_id=4933 ```
 [Maxima-bugs] [ maxima-Bugs-1430843 ] integrate(x/(1-x^2), x) and integrate(x/(x^2-1), x) From: SourceForge.net - 2011-02-12 18:49:12 ```Bugs item #1430843, was opened at 2006-02-13 13:10 Message generated for change (Settings changed) made by dgildea You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=1430843&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Lisp Core - Integration Group: None >Status: Pending Resolution: None Priority: 5 Private: No Submitted By: Raymond Toy (rtoy) Assigned to: Nobody/Anonymous (nobody) Summary: integrate(x/(1-x^2),x) and integrate(x/(x^2-1),x) Initial Comment: integrate(x/(1-x^2),x) and integrate(x/(x^2-1),x) don't ask if x < 1 or x > 1. Because of this we get two different results, when they should be equivalent, depending on the range of integration. ---------------------------------------------------------------------- Comment By: Dan Gildea (dgildea) Date: 2011-01-24 16:25 Message: (%i2) integrate(x/(1-x^2),x); (%o2) -log(1-x^2)/2 (%i3) integrate(x/(x^2-1),x); (%o3) log(x^2-1)/2 The two results are equivalent except for their sign, and a constant term of log(-1). I don't understand the problem. ---------------------------------------------------------------------- You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=1430843&group_id=4933 ```
 [Maxima-bugs] [ maxima-Bugs-1430843 ] integrate(x/(1-x^2), x) and integrate(x/(x^2-1), x) From: SourceForge.net - 2011-02-26 19:20:07 ```Bugs item #1430843, was opened at 2006-02-13 18:10 Message generated for change (Comment added) made by sf-robot You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=1430843&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Lisp Core - Integration Group: None >Status: Closed Resolution: None Priority: 5 Private: No Submitted By: Raymond Toy (rtoy) Assigned to: Nobody/Anonymous (nobody) Summary: integrate(x/(1-x^2),x) and integrate(x/(x^2-1),x) Initial Comment: integrate(x/(1-x^2),x) and integrate(x/(x^2-1),x) don't ask if x < 1 or x > 1. Because of this we get two different results, when they should be equivalent, depending on the range of integration. ---------------------------------------------------------------------- >Comment By: SourceForge Robot (sf-robot) Date: 2011-02-26 19:20 Message: This Tracker item was closed automatically by the system. It was previously set to a Pending status, and the original submitter did not respond within 14 days (the time period specified by the administrator of this Tracker). ---------------------------------------------------------------------- Comment By: Dan Gildea (dgildea) Date: 2011-01-24 21:25 Message: (%i2) integrate(x/(1-x^2),x); (%o2) -log(1-x^2)/2 (%i3) integrate(x/(x^2-1),x); (%o3) log(x^2-1)/2 The two results are equivalent except for their sign, and a constant term of log(-1). I don't understand the problem. ---------------------------------------------------------------------- You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=1430843&group_id=4933 ```