From: SourceForge.net <no...@so...> - 2010-03-24 16:14:02
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Bugs item #2975992, was opened at 2010-03-24 16:14 Message generated for change (Tracker Item Submitted) made by nobody You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2975992&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Lisp Core - Simplification Group: None Status: Open Resolution: None Priority: 5 Private: No Submitted By: Nobody/Anonymous (nobody) Assigned to: Nobody/Anonymous (nobody) Summary: partfrac problem Initial Comment: Maxima cannot solve integrate(1/x(x+4),x), but it's not an integration problem. Maxima can integrate the expression 1/(x^2+4*x) that is the exact same, but before factorisation. To be clear, try those two commands: display(integrate(1/x(x+4),x)); and display(integrate(factor(1/(x^2+4*x)),x)); ---------------------------------------------------------------------- You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2975992&group_id=4933 |
From: SourceForge.net <no...@so...> - 2010-03-24 20:22:32
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Bugs item #2975992, was opened at 2010-03-24 17:14 Message generated for change (Comment added) made by crategus You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2975992&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Lisp Core - Simplification Group: None >Status: Pending >Resolution: Invalid Priority: 5 Private: No Submitted By: Nobody/Anonymous (nobody) Assigned to: Nobody/Anonymous (nobody) Summary: partfrac problem Initial Comment: Maxima cannot solve integrate(1/x(x+4),x), but it's not an integration problem. Maxima can integrate the expression 1/(x^2+4*x) that is the exact same, but before factorisation. To be clear, try those two commands: display(integrate(1/x(x+4),x)); and display(integrate(factor(1/(x^2+4*x)),x)); ---------------------------------------------------------------------- >Comment By: Dieter Kaiser (crategus) Date: 2010-03-24 21:22 Message: Maxima can solve both integrals and they the results are equal: (%i4) integrate(1/(x*(x+4)),x); (%o4) log(x)/4-log(x+4)/4 (%i5) integrate(1/(x^2+4*x),x); (%o5) log(x)/4-log(x+4)/4 I think the multiplication operator is missing in the given example. It is 1/(x*(x+4)) and not 1/x(x+4). Setting the status to pending and the resolution to invalid. Dieter Kaiser ---------------------------------------------------------------------- You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2975992&group_id=4933 |
From: SourceForge.net <no...@so...> - 2010-04-09 02:20:28
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Bugs item #2975992, was opened at 2010-03-24 16:14 Message generated for change (Comment added) made by sf-robot You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2975992&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Lisp Core - Simplification Group: None >Status: Closed Resolution: Invalid Priority: 5 Private: No Submitted By: Nobody/Anonymous (nobody) Assigned to: Nobody/Anonymous (nobody) Summary: partfrac problem Initial Comment: Maxima cannot solve integrate(1/x(x+4),x), but it's not an integration problem. Maxima can integrate the expression 1/(x^2+4*x) that is the exact same, but before factorisation. To be clear, try those two commands: display(integrate(1/x(x+4),x)); and display(integrate(factor(1/(x^2+4*x)),x)); ---------------------------------------------------------------------- >Comment By: SourceForge Robot (sf-robot) Date: 2010-04-09 02:20 Message: This Tracker item was closed automatically by the system. It was previously set to a Pending status, and the original submitter did not respond within 14 days (the time period specified by the administrator of this Tracker). ---------------------------------------------------------------------- Comment By: Dieter Kaiser (crategus) Date: 2010-03-24 20:22 Message: Maxima can solve both integrals and they the results are equal: (%i4) integrate(1/(x*(x+4)),x); (%o4) log(x)/4-log(x+4)/4 (%i5) integrate(1/(x^2+4*x),x); (%o5) log(x)/4-log(x+4)/4 I think the multiplication operator is missing in the given example. It is 1/(x*(x+4)) and not 1/x(x+4). Setting the status to pending and the resolution to invalid. Dieter Kaiser ---------------------------------------------------------------------- You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2975992&group_id=4933 |