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From: <noreply@so...>  20020925 05:08:14

Bugs item #614203, was opened at 20020925 01:08 You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=614203&group_id=4933 Category: None Group: None Status: Open Resolution: None Priority: 5 Submitted By: Stavros Macrakis (macrakis) Assigned to: Nobody/Anonymous (nobody) Summary: Taylor gives undefined limit error Initial Comment: test: (1x^a)/(1+x^a); taylor(test,a,inf,2); asks sign of x1 If you answer pos, it works fine. If you answer zero, it gives "Break: Undefined limit product" and then "Error: Format error: arguments exhausted" (presumably there's some error in the error reporting...). The result should be zero. If you answer neg, it gives "Invalid call to varexpand". I am not sure what the correct result is, but it shouldn't cause an internal error.  You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=614203&group_id=4933 
From: SourceForge.net <noreply@so...>  20030711 22:54:44

Bugs item #614203, was opened at 20020925 01:08 Message generated for change (Comment added) made by macrakis You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=614203&group_id=4933 Category: None Group: None Status: Open Resolution: None Priority: 5 Submitted By: Stavros Macrakis (macrakis) Assigned to: Nobody/Anonymous (nobody) Summary: Taylor gives undefined limit error Initial Comment: test: (1x^a)/(1+x^a); taylor(test,a,inf,2); asks sign of x1 If you answer pos, it works fine. If you answer zero, it gives "Break: Undefined limit product" and then "Error: Format error: arguments exhausted" (presumably there's some error in the error reporting...). The result should be zero. If you answer neg, it gives "Invalid call to varexpand". I am not sure what the correct result is, but it shouldn't cause an internal error.  >Comment By: Stavros Macrakis (macrakis) Date: 20030711 18:54 Message: Logged In: YES user_id=588346 A simpler case. In this case too, the answer is trivial: since sin(x)1 == 0 , then sin(x)==1 and sin(x)^a == 1 for all a.... taylor(sin(x)^a,a,inf,2); Is SIN(x)  1 positive, negative, or zero? zero; Break: Undefined limit product Error: Format error: arguments exhausted. V "Undefined limit product ~A * ~A in limtimes lim1 lim2" Does the same for f(x) instead of sin(x). The problem appears to be that it doesn't realize that the $zero here is a *constant* zero whereas the $INF is a limiting infinity only. Constant zero * limiting infinity = zero, though of course lmiiting zero * limiting infinity is undefined.  You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=614203&group_id=4933 
From: SourceForge.net <noreply@so...>  20030713 16:44:05

Bugs item #614203, was opened at 20020925 05:08 Message generated for change (Comment added) made by kratt5 You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=614203&group_id=4933 Category: None Group: None Status: Open Resolution: None Priority: 5 Submitted By: Stavros Macrakis (macrakis) Assigned to: Nobody/Anonymous (nobody) Summary: Taylor gives undefined limit error Initial Comment: test: (1x^a)/(1+x^a); taylor(test,a,inf,2); asks sign of x1 If you answer pos, it works fine. If you answer zero, it gives "Break: Undefined limit product" and then "Error: Format error: arguments exhausted" (presumably there's some error in the error reporting...). The result should be zero. If you answer neg, it gives "Invalid call to varexpand". I am not sure what the correct result is, but it shouldn't cause an internal error.  Comment By: Martin Rubey (kratt5) Date: 20030713 16:44 Message: Logged In: YES user_id=651552 The formatting issue is reported in [ 663873 ] taylor / fixes The error remains, unfortunately... Martin  Comment By: Stavros Macrakis (macrakis) Date: 20030711 22:54 Message: Logged In: YES user_id=588346 A simpler case. In this case too, the answer is trivial: since sin(x)1 == 0 , then sin(x)==1 and sin(x)^a == 1 for all a.... taylor(sin(x)^a,a,inf,2); Is SIN(x)  1 positive, negative, or zero? zero; Break: Undefined limit product Error: Format error: arguments exhausted. V "Undefined limit product ~A * ~A in limtimes lim1 lim2" Does the same for f(x) instead of sin(x). The problem appears to be that it doesn't realize that the $zero here is a *constant* zero whereas the $INF is a limiting infinity only. Constant zero * limiting infinity = zero, though of course lmiiting zero * limiting infinity is undefined.  You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=614203&group_id=4933 
From: SourceForge.net <noreply@so...>  20060409 20:31:00

Bugs item #614203, was opened at 20020924 23:08 Message generated for change (Settings changed) made by robert_dodier You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=614203&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. >Category: Lisp Core  Taylor Group: None Status: Open Resolution: None Priority: 5 Submitted By: Stavros Macrakis (macrakis) Assigned to: Nobody/Anonymous (nobody) Summary: Taylor gives undefined limit error Initial Comment: test: (1x^a)/(1+x^a); taylor(test,a,inf,2); asks sign of x1 If you answer pos, it works fine. If you answer zero, it gives "Break: Undefined limit product" and then "Error: Format error: arguments exhausted" (presumably there's some error in the error reporting...). The result should be zero. If you answer neg, it gives "Invalid call to varexpand". I am not sure what the correct result is, but it shouldn't cause an internal error.  Comment By: Martin Rubey (kratt5) Date: 20030713 10:44 Message: Logged In: YES user_id=651552 The formatting issue is reported in [ 663873 ] taylor / fixes The error remains, unfortunately... Martin  Comment By: Stavros Macrakis (macrakis) Date: 20030711 16:54 Message: Logged In: YES user_id=588346 A simpler case. In this case too, the answer is trivial: since sin(x)1 == 0 , then sin(x)==1 and sin(x)^a == 1 for all a.... taylor(sin(x)^a,a,inf,2); Is SIN(x)  1 positive, negative, or zero? zero; Break: Undefined limit product Error: Format error: arguments exhausted. V "Undefined limit product ~A * ~A in limtimes lim1 lim2" Does the same for f(x) instead of sin(x). The problem appears to be that it doesn't realize that the $zero here is a *constant* zero whereas the $INF is a limiting infinity only. Constant zero * limiting infinity = zero, though of course lmiiting zero * limiting infinity is undefined.  You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=614203&group_id=4933 
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