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From: SourceForge.net <noreply@so...>  20100110 23:54:59

Bugs item #2922933, was opened at 20091229 18:35 Message generated for change (Comment added) made by crategus You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2922933&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Lisp Core Group: None >Status: Closed >Resolution: Invalid Priority: 5 Private: No Submitted By: Rui Maciel (rui_maciel) Assigned to: Nobody/Anonymous (nobody) Summary: Defining function from expression doesn't relate arguments Initial Comment: Let's say we have the following expression: a: (x  1)*x*(y  1)*y*(z  1)*z/8; and let's say we declare the following function: f(x,y,z) := a; If we pass arguments to that function, the function fails to replace the expression's variables with the value of the arguments passed to the function. For example: (%i387) f(0,0,0); (x  1) x (y  1) y (z  1) z (%o387)  8 Yet, if the expression's variables are substituted in the function declaration then everything works as expected: (%i388) f(b,c,d) := subst([x=b,y=c,z=d],a); (%o388) f(b, c, d) := subst([x = b, y = c, z = d], a) (%i389) f(0,0,0); (%o389) 0 That extra call to subst() should not be needed in order to successfully declare a function from an expression.  >Comment By: Dieter Kaiser (crategus) Date: 20100111 00:54 Message: Yes, that is the expected behaviour. The operator := does not evaluate its argument. (%i18) a:((x  1)*x*(y  1)*y*(z  1))*z/8$ If you use the symbol a in the definition, you get a function which is defined to return the symbol a or the value of the symbol a. (%i20) f(x,y,z):=a; (%o20) f(x,y,z):=a You have to doublequote the symbol a to insert the value of a: (%i21) f(x,y,z):=''a; (%o21) f(x,y,z):=(x1)*x*(y1)*y*(z1)*z/8 Again, using the doublequoted %operator: (%i26) a; (%o26) (x1)*x*(y1)*y*(z1)*z/8 (%i27) f(x,y,z):=''%; (%o27) f(x,y,z):=(x1)*x*(y1)*y*(z1)*z/8 Closing this bug report as invalid. Dieter Kaiser  Comment By: Rui Maciel (rui_maciel) Date: 20091230 11:40 Message: That's weird. It appears it works with the define() function but if the := operator is used directly then the function definition fails. For example: (%i1) (x  1)*x*(y  1)*y*(z  1)*z/8; (%o1) ((x  1)*x*(y  1)*y*(z  1))*z/8; (%i2) f(x,y,z) := %; (%o2) f(x, y, z) := % (%i3) f(0,0,0); (%o3) f(x, y, z) := % (%i4) define(f(x,y,z), %o1); (%o4) f(x, y, z) := ((x  1)*x*(y  1)*y*(z  1)*z)/8 (%i5) f(0,0,0); (%o5) 0 Is this a bug or is this behaviour expected?  Comment By: Aleksas Domarkas (alex108) Date: 20091230 06:56 Message: You can successfully declare a function from an expression: (%i1) (x  1)*x*(y  1)*y*(z  1)*z/8; (%o1) ((x1)*x*(y1)*y*(z1)*z)/8 (%i2) define(f(x,y,z),%); (%o2) f(x,y,z):=((x1)*x*(y1)*y*(z1)*z)/8 (%i3) f(0,0,0); (%o3) 0  You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2922933&group_id=4933 
From: SourceForge.net <noreply@so...>  20100110 23:35:12

Bugs item #2927502, was opened at 20100107 13:57 Message generated for change (Comment added) made by crategus You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2927502&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Lisp Core  Complex Group: None >Status: Closed >Resolution: Fixed Priority: 5 Private: No Submitted By: Stanislav Maslovski (s_i_m) Assigned to: Nobody/Anonymous (nobody) Summary: abs() or cabs() are much slower than just sqrt(re^2+im^2) Initial Comment: Doing some calculations I noticed that there is something wrong with imlementation of abs() and cabs(). Basically, in the code below I can calculate and plot sqrt(re^2 + im^2), but I cannot do it with abs(), nor with cabs(): it never finishes and Maxima does not react to the keyboard interrupt either. I run this version of maxima (on Debian sid): Maxima 5.20.1 http://maxima.sourceforge.net using Lisp GNU Common Lisp (GCL) GCL 2.6.7 (a.k.a. GCL) ======================================================== eps : [1,2]; mu : [1,1]; n : sqrt(eps*mu); vc : [0,0.5]; epst : eps*(1vc^2)/(1n^2*vc^2); mut : mu*(1vc^2)/(1n^2*vc^2); a : vc*(n^21)/(1n^2*vc^2); kxe : %i*sqrt(k0^2*eps*mut+eps/epst*(kz+k0*a)^2+ky^2); kxh : %i*sqrt(k0^2*mu*epst+mu/mut*(kz+k0*a)^2+ky^2); betae : k0*kxe*epst/(k0^2*epst*mut(kz+k0*a)^2); betah : k0*kxh*mut/(k0^2*epst*mut(kz+k0*a)^2); alpha : ky*(kz+k0*a)/(k0^2*epst*mut(kz+k0*a)^2); a1 : part(alpha,1); a2 : part(alpha,2); be1 : part(betae,1); be2 : part(betae,2); bh1 : part(betah,1); bh2 : part(betah,2); denom : (a1a2)^2+(be1+be2)*(bh1+bh2); Ree : ((a1a2)^2(be1be2)*(bh1+bh2))/denom; plot3d(sqrt(realpart(subst(k0=%i,Ree))^2+imagpart(subst(k0=%i,Ree))^2),[ky,3,3],[kz,3,3]); plot3d(cabs(subst(k0=%i,Ree)),[ky,3,3],[kz,3,3]); plot3d(abs(subst(k0=%i,Ree)),[ky,3,3],[kz,3,3]);  >Comment By: Dieter Kaiser (crategus) Date: 20100111 00:35 Message: Fixed in revision 1.28 in rpart.lisp. An extra expand in the routine absarg has been removed. This expand has caused an enormous growing of the expression of this example. With this change the time to get the rectform and the absolute value are comparable. The plot for the absolute value is faster than the plot with the sqrt function. Example with sbcl on a slow notebook: (%i7) plot3d(sqrt(realpart(test)^2 +imagpart(test)^2),[ky,3,3],[kz,3,3]); Evaluation took 119.8990 seconds (122.6900 elapsed) using 3259.698 MB. (%o7) false (%i8) plot3d(abs(test),[ky,3,3],[kz,3,3]); Evaluation took 54.8320 seconds (56.3300 elapsed) using 628.454 MB. (%o8) false Closing this bug report as fixed. Dieter Kaiser  You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2927502&group_id=4933 