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From: SourceForge.net <noreply@so...>  20090901 21:00:02

Bugs item #2848682, was opened at 20090901 21:51 Message generated for change (Comment added) made by crategus You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2848682&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Lisp Core  Assume Group: None Status: Open Resolution: None Priority: 5 Private: No Submitted By: Dieter Kaiser (crategus) Assigned to: Nobody/Anonymous (nobody) Summary: abs(log(1)) > log(1) Initial Comment: Maxima always simplifies abs(log(x)) to log(x) if x<1: (%i38) assume(x<0)$ (%i39) abs(log(x)); (%o39) log(x) This happens for negative numbers too: (%i40) abs(log(1)); (%o40) log(1) As a consequence the absolute value of e.g. log(1) is imaginary: (%i45) rectform(abs(log(1))); (%o45) %i*%pi This is the correct result: (%i46) abs(rectform(log(1))); (%o46) %pi The reason is that for every argument x<1 the function sign returns neg. (%i42) sign(log(x)); (%o42) neg But this is true only for 0 < x < 1. For x<0 sign should return pnz. This could be a correction to the routine sign in compar.lisp: ((eq (caar x) '%log) ;; Return a negative or positive sign only when the argument ;; is a real positive value in all other cases '$pnz. (cond ((eq (setq sign (compare (cadr x) 0)) '$neg) ;; Negative argument. (setq sign '$pnz)) (t ;; Positive argument to the Log function. ;; Check argument < 1 or > 1. (compare (cadr x) 1)))) Dieter Kaiser  >Comment By: Dieter Kaiser (crategus) Date: 20090901 22:59 Message: Remark: When we improve the routine sign for the log function, we get one error with the testsuite: Running tests in rtest16: ********************** Problem 112 *************** Input: limit(abs(log(x)), x, 0) Result: 'limit(abs(log(x)),x,0) This differed from the expected result: inf We get again the expected limit, when we improve the limit for the absolute value too. Dieter Kaiser  You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2848682&group_id=4933 
From: SourceForge.net <noreply@so...>  20090901 19:51:19

Bugs item #2848682, was opened at 20090901 21:51 Message generated for change (Tracker Item Submitted) made by crategus You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2848682&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Lisp Core  Assume Group: None Status: Open Resolution: None Priority: 5 Private: No Submitted By: Dieter Kaiser (crategus) Assigned to: Nobody/Anonymous (nobody) Summary: abs(log(1)) > log(1) Initial Comment: Maxima always simplifies abs(log(x)) to log(x) if x<1: (%i38) assume(x<0)$ (%i39) abs(log(x)); (%o39) log(x) This happens for negative numbers too: (%i40) abs(log(1)); (%o40) log(1) As a consequence the absolute value of e.g. log(1) is imaginary: (%i45) rectform(abs(log(1))); (%o45) %i*%pi This is the correct result: (%i46) abs(rectform(log(1))); (%o46) %pi The reason is that for every argument x<1 the function sign returns neg. (%i42) sign(log(x)); (%o42) neg But this is true only for 0 < x < 1. For x<0 sign should return pnz. This could be a correction to the routine sign in compar.lisp: ((eq (caar x) '%log) ;; Return a negative or positive sign only when the argument ;; is a real positive value in all other cases '$pnz. (cond ((eq (setq sign (compare (cadr x) 0)) '$neg) ;; Negative argument. (setq sign '$pnz)) (t ;; Positive argument to the Log function. ;; Check argument < 1 or > 1. (compare (cadr x) 1)))) Dieter Kaiser  You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2848682&group_id=4933 