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From: SourceForge.net <noreply@so...>  20090301 17:44:05

Bugs item #2652359, was opened at 20090301 18:43 Message generated for change (Tracker Item Submitted) made by Item Submitter You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2652359&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Xmaxima or other UI Group: None Status: Open Resolution: None Priority: 5 Private: No Submitted By: David StrĂ¶m (dmaj26) Assigned to: Nobody/Anonymous (nobody) Summary: wxMaxima 0.8.0 hungup on 'collectterms' Initial Comment:  Maxima version: 5.17.0 Maxima build date: 19:8 12/4/2008 host type: i686pcmingw32 lispimplementationtype: GNU Common Lisp (GCL) lispimplementationversion: GCL 2.6.8  The elder wxMaximaversion did not have this bug. Nor does xMaxima itself. expand((x+a)*(x+b));collectterms(%,x); results in a neverending list of empty %o:s on the screen. Button for interrupt does not work, so I have to end program with Windows Task Manager.  You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2652359&group_id=4933 
From: SourceForge.net <noreply@so...>  20090301 17:24:29

Bugs item #2651868, was opened at 20090301 16:12 Message generated for change (Comment added) made by digital7 You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2651868&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Lisp Core  Integration Group: None >Status: Open Resolution: Invalid Priority: 5 Private: No Submitted By: Denis (digital7) Assigned to: Nobody/Anonymous (nobody) Summary: integrate(sin(a*x+b)^2,x); incorrect answer. Initial Comment: (%i39) integrate(sin(a*x+b)^2, x); (%o39) (sin(2*(a*x+b))/2+a*x+b)/(2*a) And after that: (%i42) expand((sin(2*(a*x+b))/2+a*x+b)/(2*a)); (%o42) sin(2*a*x+2*b)/(4*a)+x/2+b/(2*a) But using risch function and integrating myself I've got another results: (%i40) risch(sin(a*x+b)^2, x); (%o40) (sin(2*a*x+2*b)2*a*x)/(4*a) sin(x)^2 = 1/2 * (1  cos(2*x)) => sin(a*x+b)^2 = 1/2 * (1  cos(2*a*x + 2*b)) \ \ \ sin(a*x+b)^2 dx = 1/2 * (dx  cos(2*a*x + 2*b)dx) = \ \ \ = x/2  1/(2*a) * sin(2*a*x + 2*b) What does "b/(2*a)" mean? Where have maxima got it? P.S. I've attached a wxMaxima session file with these calculations. Best regards, Denis.  >Comment By: Denis (digital7) Date: 20090301 19:24 Message: Thank you for your answer. Because I was calculating a definite integral for my complex work and checking the integration if Maxima, I haven't noticed that b/(2*a) is a constant. Some time later I'll dig into the integration routines. :) I think that topic is closed. Thank you again.  Comment By: Raymond Toy (rtoy) Date: 20090301 18:00 Message: Both results are correct. They only differ by the constant b/(2*a). The derivative of each, after some manipulations, equals the integrand. Not sure what you're asking about "b/(2*a)". If you really want to know how maxima got it you'll have to dig into the integration routines. Marking as pending/invalid. Please update if this analysis is incorrect.  You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2651868&group_id=4933 
From: SourceForge.net <noreply@so...>  20090301 16:25:50

Bugs item #2650081, was opened at 20090228 19:13 Message generated for change (Comment added) made by dgildea You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2650081&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Lisp Core  Integration Group: None >Status: Closed >Resolution: Fixed Priority: 5 Private: No Submitted By: Dieter Kaiser (crategus) Assigned to: Nobody/Anonymous (nobody) Summary: integrate(atan(y),y,x,inf) loops endlessly Initial Comment: Maxima does not finish the calculation of the integral. After a (very) long time Maxima gets a stack overflow. (%i1) integrate(atan(y),y,x,inf); ***  Program stack overflow. RESET [/build/buildd/clisp2.44.1/src/eval.d:527] reset() found no driver frame (sp=0xbfea64300xbfea0200) Exiting on signal 6 Aborted I think the integral should be divergent. Dieter Kaiser  >Comment By: Dan Gildea (dgildea) Date: 20090301 11:25 Message: Fixed in limit.lisp rev 1.65.  You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2650081&group_id=4933 
From: SourceForge.net <noreply@so...>  20090301 16:00:26

Bugs item #2651868, was opened at 20090301 09:12 Message generated for change (Comment added) made by rtoy You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2651868&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Lisp Core  Integration Group: None >Status: Pending >Resolution: Invalid Priority: 5 Private: No Submitted By: Denis (digital7) Assigned to: Nobody/Anonymous (nobody) Summary: integrate(sin(a*x+b)^2,x); incorrect answer. Initial Comment: (%i39) integrate(sin(a*x+b)^2, x); (%o39) (sin(2*(a*x+b))/2+a*x+b)/(2*a) And after that: (%i42) expand((sin(2*(a*x+b))/2+a*x+b)/(2*a)); (%o42) sin(2*a*x+2*b)/(4*a)+x/2+b/(2*a) But using risch function and integrating myself I've got another results: (%i40) risch(sin(a*x+b)^2, x); (%o40) (sin(2*a*x+2*b)2*a*x)/(4*a) sin(x)^2 = 1/2 * (1  cos(2*x)) => sin(a*x+b)^2 = 1/2 * (1  cos(2*a*x + 2*b)) \ \ \ sin(a*x+b)^2 dx = 1/2 * (dx  cos(2*a*x + 2*b)dx) = \ \ \ = x/2  1/(2*a) * sin(2*a*x + 2*b) What does "b/(2*a)" mean? Where have maxima got it? P.S. I've attached a wxMaxima session file with these calculations. Best regards, Denis.  >Comment By: Raymond Toy (rtoy) Date: 20090301 11:00 Message: Both results are correct. They only differ by the constant b/(2*a). The derivative of each, after some manipulations, equals the integrand. Not sure what you're asking about "b/(2*a)". If you really want to know how maxima got it you'll have to dig into the integration routines. Marking as pending/invalid. Please update if this analysis is incorrect.  You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2651868&group_id=4933 
From: SourceForge.net <noreply@so...>  20090301 14:12:13

Bugs item #2651868, was opened at 20090301 16:12 Message generated for change (Tracker Item Submitted) made by Item Submitter You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2651868&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Lisp Core  Integration Group: None Status: Open Resolution: None Priority: 5 Private: No Submitted By: Denis (digital7) Assigned to: Nobody/Anonymous (nobody) Summary: integrate(sin(a*x+b)^2,x); incorrect answer. Initial Comment: (%i39) integrate(sin(a*x+b)^2, x); (%o39) (sin(2*(a*x+b))/2+a*x+b)/(2*a) And after that: (%i42) expand((sin(2*(a*x+b))/2+a*x+b)/(2*a)); (%o42) sin(2*a*x+2*b)/(4*a)+x/2+b/(2*a) But using risch function and integrating myself I've got another results: (%i40) risch(sin(a*x+b)^2, x); (%o40) (sin(2*a*x+2*b)2*a*x)/(4*a) sin(x)^2 = 1/2 * (1  cos(2*x)) => sin(a*x+b)^2 = 1/2 * (1  cos(2*a*x + 2*b)) \ \ \ sin(a*x+b)^2 dx = 1/2 * (dx  cos(2*a*x + 2*b)dx) = \ \ \ = x/2  1/(2*a) * sin(2*a*x + 2*b) What does "b/(2*a)" mean? Where have maxima got it? P.S. I've attached a wxMaxima session file with these calculations. Best regards, Denis.  You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2651868&group_id=4933 
From: SourceForge.net <noreply@so...>  20090301 12:53:41

Bugs item #2647130, was opened at 20090227 18:49 Message generated for change (Comment added) made by willisbl You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2647130&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: None Group: None Status: Closed Resolution: Invalid Priority: 5 Private: No Submitted By: Nobody/Anonymous (nobody) Assigned to: Nobody/Anonymous (nobody) Summary: 2^2^3 = 256 Initial Comment: wxMaxima 0.8.1 2^2^3 = 256 shouldn't this result in 64?  >Comment By: Barton Willis (willisbl) Date: 20090301 06:53 Message: No, 256 is correct. Maxima's "^" operator is right associative. Thus 2^2^3 = 2^(2^3) = 2^8 = 256.  Comment By: Barton Willis (willisbl) Date: 20090301 06:53 Message: No, 256 is correct. Maxima's "^" operator is right associative. Thus 2^2^3 = 2^(2^3) = 2^8 = 256.  You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2647130&group_id=4933 
From: SourceForge.net <noreply@so...>  20090301 12:53:22

Bugs item #2647130, was opened at 20090227 18:49 Message generated for change (Comment added) made by willisbl You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2647130&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: None Group: None >Status: Closed >Resolution: Invalid Priority: 5 Private: No Submitted By: Nobody/Anonymous (nobody) Assigned to: Nobody/Anonymous (nobody) Summary: 2^2^3 = 256 Initial Comment: wxMaxima 0.8.1 2^2^3 = 256 shouldn't this result in 64?  >Comment By: Barton Willis (willisbl) Date: 20090301 06:53 Message: No, 256 is correct. Maxima's "^" operator is right associative. Thus 2^2^3 = 2^(2^3) = 2^8 = 256.  You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2647130&group_id=4933 
From: SourceForge.net <noreply@so...>  20090301 00:13:34

Bugs item #2650081, was opened at 20090301 01:13 Message generated for change (Tracker Item Submitted) made by Item Submitter You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2650081&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Lisp Core  Integration Group: None Status: Open Resolution: None Priority: 5 Private: No Submitted By: Dieter Kaiser (crategus) Assigned to: Nobody/Anonymous (nobody) Summary: integrate(atan(y),y,x,inf) loops endlessly Initial Comment: Maxima does not finish the calculation of the integral. After a (very) long time Maxima gets a stack overflow. (%i1) integrate(atan(y),y,x,inf); ***  Program stack overflow. RESET [/build/buildd/clisp2.44.1/src/eval.d:527] reset() found no driver frame (sp=0xbfea64300xbfea0200) Exiting on signal 6 Aborted I think the integral should be divergent. Dieter Kaiser  You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2650081&group_id=4933 