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From: SourceForge.net <noreply@so...>  20081008 15:05:59

Bugs item #2142758, was opened at 20081002 13:01 Message generated for change (Comment added) made by rtoy You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2142758&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Lisp Core  Integration Group: None >Status: Closed >Resolution: Fixed Priority: 5 Private: No Submitted By: Nobody/Anonymous (nobody) Assigned to: Nobody/Anonymous (nobody) Summary: integrate(sqrt(22*x^2)*(sqrt(2)*x^2+sqrt(2))/(44*x^2),x,0, Initial Comment: I'm using Maxima 5.16.3 integrate(sqrt(22*x^2)*(sqrt(2)*x^2+sqrt(2))/(44*x^2),x,0,1); evaluates to 3*%pi/4, which is wrong (should be positive and equal to 3*%pi/8). If one simplifies this expression to integrate(sqrt(1x^2)*(x^2+1)/(22*x^2),x,0,1); it evaluates still to 3*%pi/4. But this: integrate(sqrt(1x^2)*(x^2+1)/(1x^2),x,0,1); evaluates correctly to 3*%pi/4 Hope this helps you to improve this really great program! My best regards to all who contribute. Ivo email: ivo dot bloechliger at kanti dash wohlen dot ch  >Comment By: Raymond Toy (rtoy) Date: 20081008 11:05 Message: Fixed in irinte.lisp, rev 1.23.  Comment By: Raymond Toy (rtoy) Date: 20081008 10:51 Message: The problem is caused by the routine pnsintir3 in irinte.lisp. A typo in the derivation (and implementation) caused the integrand to be multiplied by an extra 4. After fixing this, maxima now returns 3*%pi/8.  Comment By: Raymond Toy (rtoy) Date: 20081006 11:52 Message: FWIW, maxima computes all of these definite integrals by computing the antiderivative and substituting the limits. For all but the last integral, the antiderivative has the wrong sign. I do not know why the sign is wrong.  You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2142758&group_id=4933 
From: SourceForge.net <noreply@so...>  20081008 14:51:40

Bugs item #2142758, was opened at 20081002 13:01 Message generated for change (Comment added) made by rtoy You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2142758&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Lisp Core  Integration Group: None Status: Open Resolution: None Priority: 5 Private: No Submitted By: Nobody/Anonymous (nobody) Assigned to: Nobody/Anonymous (nobody) Summary: integrate(sqrt(22*x^2)*(sqrt(2)*x^2+sqrt(2))/(44*x^2),x,0, Initial Comment: I'm using Maxima 5.16.3 integrate(sqrt(22*x^2)*(sqrt(2)*x^2+sqrt(2))/(44*x^2),x,0,1); evaluates to 3*%pi/4, which is wrong (should be positive and equal to 3*%pi/8). If one simplifies this expression to integrate(sqrt(1x^2)*(x^2+1)/(22*x^2),x,0,1); it evaluates still to 3*%pi/4. But this: integrate(sqrt(1x^2)*(x^2+1)/(1x^2),x,0,1); evaluates correctly to 3*%pi/4 Hope this helps you to improve this really great program! My best regards to all who contribute. Ivo email: ivo dot bloechliger at kanti dash wohlen dot ch  Comment By: Raymond Toy (rtoy) Date: 20081008 10:51 Message: The problem is caused by the routine pnsintir3 in irinte.lisp. A typo in the derivation (and implementation) caused the integrand to be multiplied by an extra 4. After fixing this, maxima now returns 3*%pi/8.  Comment By: Raymond Toy (rtoy) Date: 20081006 11:52 Message: FWIW, maxima computes all of these definite integrals by computing the antiderivative and substituting the limits. For all but the last integral, the antiderivative has the wrong sign. I do not know why the sign is wrong.  You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2142758&group_id=4933 
From: SourceForge.net <noreply@so...>  20081008 03:31:15

Bugs item #2149039, was opened at 20081006 02:16 Message generated for change (Comment added) made by robert_dodier You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2149039&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. >Category: Lisp Core Group: None >Status: Closed >Resolution: Rejected Priority: 5 Private: No Submitted By: Nobody/Anonymous (nobody) Assigned to: Nobody/Anonymous (nobody) Summary: function is works not correct Initial Comment: Maxima 5.16.3 (%i4) is((ab)/(cd)=(ba)/(dc)); (%o4) false MuPad, Mathematica and Maple's answers are: true for example: MuPad 4.0.6 is((ab)/(cd)=(ba)/(dc)) TRUE wolfgang.below@...  >Comment By: Robert Dodier (robert_dodier) Date: 20081007 21:31 Message: In Maxima, "=" means literal equality (i.e. same expression) while "equal" means equivalence (equal value). is (equal ((a  b)/(c  d), (b  a)/(d  c))); => true Closing this report as it is not a bug.  Comment By: Raymond Toy (rtoy) Date: 20081006 07:22 Message: I think you want to use equal: is(equal((ab)/(cd), (ba)/(dc)) > true  You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2149039&group_id=4933 
From: Web User <www@us...>  20081008 02:20:31

Bugs item #2125317, was opened at 20080923 22:30 Message generated for change (Comment added) made by sfrobot You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2125317&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Xmaxima or other UI Group: None >Status: Closed Resolution: Invalid Priority: 5 Private: No Submitted By: Lindsay Dunseith (dunseith) Assigned to: Nobody/Anonymous (nobody) Summary: Multiplication of matrices Initial Comment: For the matrix " matrix M =([m,0],[0,m]), the power M^n is determined correctly. However, for other matrices, e.g. P =([3,1],[1,3])Maxima determines P^2 as matrix([9,1],[1,9]), instead of the correct: matrix([10,6],[6,10]) I haven't tried multiplying more general matrices, but does this mean there is a problem with matrix multiplication? Maxima build as follows: Maxima version: 5.15.0 Maxima build date: 17:36 4/20/2008 host type: i686pcmingw32 lispimplementationtype: GNU Common Lisp (GCL) lispimplementationversion: GCL 2.6.8  >Comment By: SourceForge Robot (sfrobot) Date: 20081008 02:20 Message: This Tracker item was closed automatically by the system. It was previously set to a Pending status, and the original submitter did not respond within 14 days (the time period specified by the administrator of this Tracker).  Comment By: Barton Willis (willisbl) Date: 20081001 11:55 Message: Another thing: to square a matrix, use "^^" not "^".  Comment By: Raymond Toy (rtoy) Date: 20080924 00:05 Message: Please be more explicit and show exactly what you did. However, I suspect you used * to multiply matrices. This is an elementbyelement multiply. The matrix multiply operator is ".". So: p:matrix([3,1],[1,3]); p . p; matrix([10,6],[6,10]) Marking as pending/invalid.  You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=2125317&group_id=4933 