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From: SourceForge.net <noreply@so...>  20080313 15:06:58

Bugs item #1913588, was opened at 20080313 08:06 Message generated for change (Tracker Item Submitted) made by Item Submitter You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=1913588&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Lisp Core  Polynomials Group: None Status: Open Resolution: None Priority: 5 Private: No Submitted By: Nobody/Anonymous (nobody) Assigned to: Nobody/Anonymous (nobody) Summary: algsys hangs Initial Comment: algsys hangs on the following input: eq1 : a*x + c*y + d*y^2/2 = 0; eq2 : b*x + e*x^2 + f*y  g*y^3 = h; algsys([eq1,eq2],[x,y]); System information: Maxima version: 5.12.0 Maxima build date: 15:52 7/20/2007 host type: i686pclinuxgnu lispimplementationtype: GNU Common Lisp (GCL) lispimplementationversion: GCL 2.6.7  You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=1913588&group_id=4933 
From: SourceForge.net <noreply@so...>  20080313 12:05:52

Bugs item #1569644, was opened at 20061002 20:15 Message generated for change (Settings changed) made by dgildea You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=1569644&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Lisp Core  Simplification Group: None >Status: Closed >Resolution: Works For Me Priority: 5 Private: No Submitted By: Stavros Macrakis (macrakis) Assigned to: Nobody/Anonymous (nobody) Summary: expand(ceiling(...)) doesn't look inside Initial Comment: expand(ceiling(x*(x1))) doesn't expand the product.  Comment By: Harald Geyer (hgeyer) Date: 20070618 14:26 Message: Logged In: YES user_id=929336 Originator: NO I can't reproduce this bug with maxima 5.12.0 CLISP. I guess this problem has been fixed in the meanwhile. I think this bug report should be closed. Regards, Harald  Comment By: Barton Willis (willisbl) Date: 20061002 20:30 Message: Logged In: YES user_id=895922 Deleting the simp flag check in simpceiling fixes this bug. I assume that all the other functions in nummod.lisp have similar bugs. I'll fix these bugs.  You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=1569644&group_id=4933 
From: SourceForge.net <noreply@so...>  20080313 09:33:12

Bugs item #1909488, was opened at 20080307 06:08 Message generated for change (Settings changed) made by willisbl You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=1909488&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: None Group: None >Status: Closed >Resolution: Invalid Priority: 5 Private: No Submitted By: Nobody/Anonymous (nobody) Assigned to: Nobody/Anonymous (nobody) Summary: mnewton bug Initial Comment: The 3rd example given does not work. Reference: http://maxima.sourceforge.net/docs/manual/en/ maxima_63.html#Item_003aIntroductiontomnewton (%i1) load("mnewton")$ (%i2) mnewton([x1+3*log(x1)x2^2, 2*x1^2x1*x25*x1+1], [x1, x2], [5, 5]); (%o2) [[x1=3.822890025575447,x2=2.807544757033248]] (%i3) mnewton([2*a^a5],[a],[1]); (%o3) [[a=1.70927556786144]] (%i4) mnewton([2*3^uv/u5, u+2^v4], [u, v], [2, 2]); Polynomial quotient is not exact#0: mnewton(funclist=[v/u+2*3^u5,2^v+u4],varlist=[u,v],guesslist=[2,2])(mnewton.mac line 89)  an error. To debug this try debugmode(true);(%i5)  Comment By: Nobody/Anonymous (nobody) Date: 20080308 23:13 Message: Logged In: NO That must be it, this is my build info (%i1) build_info()$ Maxima version: 5.12.0 Maxima build date: 15:52 7/20/2007 host type: i686pclinuxgnu lispimplementationtype: GNU Common Lisp (GCL)lispimplementationversion: GCL 2.6.7  Comment By: Barton Willis (willisbl) Date: 20080307 17:21 Message: Logged In: YES user_id=895922 Originator: NO It works for me; maybe you have an old version. (%i2) mnewton([2*3^uv/u5, u+2^v4], [u, v], [2, 2]); (%o2) [[u=1.066618389595407,v=1.552564766841786]] (%i8) build_info(); Maxima version: 5.14.0 Maxima build date: 21:46 12/27/2007 host type: i686pcmingw32 lispimplementationtype: GNU Common Lisp (GCL) lispimplementationversion: GCL 2.6.8  You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=1909488&group_id=4933 
From: SourceForge.net <noreply@so...>  20080313 09:32:31

Bugs item #1910043, was opened at 20080308 06:12 Message generated for change (Settings changed) made by willisbl You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=1910043&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Lisp Core  Complex Group: None >Status: Closed Resolution: Invalid Priority: 5 Private: No Submitted By: Nobody/Anonymous (nobody) Assigned to: Nobody/Anonymous (nobody) Summary: Wrong calculation with nested matrices Initial Comment: If I am not mistaking, these two calculations should yield the same result, but do not in Maxima: input: matrix([0,0,0,1],[0,0,1,0],[0,1,0,0],[1,0,0,0]).matrix([0,0,0,%i],[0,0,%i,0],[0,%i,0,0],[ %i,0,0,0]); output: matrix([%i,0,0,0],[0,%i,0,0],[0,0,%i,0],[0,0,0,%i]) input: matrix([0,matrix([0,1],[1,0])],[matrix([0,1],[1,0]),0]).matrix([0,matrix([0,%i],[%i,0])],[matrix([0,%i],[%i,0]),0]); output: matrix([matrix([0,%i],[%i,0]),matrix([0,0],[0,0])],[matrix([0,0],[0,0]),matrix([0,%i],[%i,0])]) thus, there is something wrong, or am I wrong with that? Maxima version: 5.12.0Maxima build date: 15:52 7/20/2007host type: i686pclinuxgnulispimplementationtype: GNU Common Lisp (GCL)lispimplementationversion: GCL 2.6.7  Comment By: Barton Willis (willisbl) Date: 20080308 10:11 Message: Logged In: YES user_id=895922 Originator: NO I don't think we want to default matrix_element_mult to "."; suppose a, b, c, and d are identifiers for real numbers. Then (%i23) m1 : matrix([a,b],[c,d])$ (%i25) m2 : matrix([d,b],[c,a])$ (%i26) matrix_element_mult : "."$ (%i27) m1 . m2; (%o27) matrix([a.db.c,b.aa.b],[c.dd.c,d.ac.b]) With noncommutative multiplication, the offdiagonal terms are nonzero, but with commutative multiplication, the offdiagonal terms are zero. That is correct for a,b,c,d real numbers. (%i28) matrix_element_mult : "*"$ (%i29) m1 . m2; (%o29) matrix([a*db*c,0],[0,a*db*c])  Comment By: fabus (fgebert) Date: 20080308 09:22 Message: Logged In: YES user_id=1126735 Originator: NO I did not know matrix_element_mult. Is there anything against defaulting matrix_element_mult to "."?  Comment By: Barton Willis (willisbl) Date: 20080308 08:25 Message: Logged In: YES user_id=895922 Originator: NO To work with nested (or block) matrices, you'll need to set matrix_element_mult to ".". Try this (%i17) matrix_element_mult : "."$ (%i18) matrix([0,matrix([0,1],[1,0])],[matrix([0,1],[1,0]),0]).matrix([0,matrix([0,%i],[%i,0])],[matrix([0,%i],[ %i,0]),0])$ (%i20) mat_unblocker(%); (%o20) matrix([%i,0,0,0],[0,%i,0,0],[0,0,%i,0],[0,0,0,%i])  You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=1910043&group_id=4933 
From: SourceForge.net <noreply@so...>  20080313 00:30:31

Bugs item #1913067, was opened at 20080312 17:06 Message generated for change (Comment added) made by rtoy You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=1913067&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Lisp Core  Integration Group: None Status: Open Resolution: None Priority: 5 Private: No Submitted By: Ximin Luo (infinity0x) Assigned to: Nobody/Anonymous (nobody) Summary: Cannot integrate 1/(1+x^n) Initial Comment: Maxima cannot integrate functions of the form 1/(1+x^n) for n >= 7. Mathematica is capable of this. Maxima attempts the integration via an algorithm which seems to involve taking partial fractions. For example, if you try to integrate 1/(1+x^7) for example, Maxima gives: log(1+x)/7  integral(x^52*x^4+3*x^34*x^2+5*x6)/(x^6x^5+x^4x^3+x^2x+1) / 7 I'm guessing a different algorithm (such as that employed by Mathematica) is required to give a fully symbolic answer. For the record, the integral(1/(1+x^7)) is: Log[1 + x]/7  (Cos[Pi/7]*Log[1 + x^2  2*x*Cos[Pi/7]])/7  (Cos[(3*Pi)/7]*Log[1 + x^2  2*x*Cos[(3*Pi)/7]])/7  (Cos[(5*Pi)/7]*Log[1 + x^2  2*x*Cos[(5*Pi)/7]])/7 + (2*ArcTan[(x  Cos[Pi/7])*Csc[Pi/7]]* Sin[Pi/7])/7 + (2*ArcTan[(x  Cos[(3*Pi)/7])* Csc[(3*Pi)/7]]*Sin[(3*Pi)/7])/7 + (2*ArcTan[(x  Cos[(5*Pi)/7])* Csc[(5*Pi)/7]]*Sin[(5*Pi)/7])/7  Additionally, this also means that we can calculate the integral(that nasty rational function), by calculating 7 * ( log(1+x)/7  integral(1/(1+x^7)) ) As a side note, Mathematica also cannot give integral(that nasty rational function) fully symbolically. Instead, it gives: RootSum[1  #1 + #1^2  #1^3 + #1^4  #1^5 + #1^6 & , (6*Log[x  #1] + 5*Log[x  #1]*#1  4*Log[x  #1]*#1^2 + 3*Log[x  #1]* #1^3  2*Log[x  #1]*#1^4 + Log[x  #1]*#1^5)/(1 + 2*#1  3*#1^2 + 4*#1^3  5*#1^4 + 6*#1^5) & ] where RootSum[ f, form ] represents the sum of form[x] for all x that satisfy the polynomial equation f[x] == 0.  >Comment By: Raymond Toy (rtoy) Date: 20080312 20:30 Message: Logged In: YES user_id=28849 Originator: NO Actually, the roots are obviously the seven roots of 1, which maxima does know, and it could have done the partial fraction expansion to find the value of the integral. Not sure how or where to teach maxima about this, though. Some thought needed.  Comment By: Ximin Luo (infinity0x) Date: 20080312 18:32 Message: Logged In: YES user_id=2003896 Originator: YES The point is that Maxima does not NEED to know the roots of that equation. Sorry for making this unclear. By doing the integral using a different algorithm which doesn't involve taking partial fractions, you can avoid the above, and get a purely symbolic integral, like Mathematic does.  Comment By: Raymond Toy (rtoy) Date: 20080312 18:16 Message: Logged In: YES user_id=28849 Originator: NO Maxima can't give an answer because it doesn't know the roots of (x^7+1)/(x+1). If you set integrate_use_rootsof:true, then maxima can return an answer, but unless you can compute the roots of the above equation, it's probably not very helpful.  You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=1913067&group_id=4933 