#189 integrate( 1/((x+1)^2*(x-1)^4)^(1/3),x ) not solved

[Trevor Clavijo]

5.47.0

(%i16) func01(x) := 1/((x+1)^2*(x-1)^4)^(1/3);
                                             1
(%o16)                func01(x) := ----------------------
                                           2        4 1/3
                                   ((x + 1)  (x - 1) )
(%i17) integrate( func01(x), x );
                          /
                          [           1
(%o17)                    I --------------------- dx
                          ]        4/3        2/3
                          / (x - 1)    (x + 1)

In fact
func01(x) == 1/(x^2-1)*((x+1)/(x-1))^(1/3)

t := ((x+1)/(x-1))^(1/3)
=>
x == (t^3+1)/(t^3-1)
dx == (6t^2)/(t^3-1)^2dt

%i17 == -3/2t

[Trevor Clavijo]

please consider filing a feature request

[Trevor Clavijo]

I'll no longer submit such questions as bugs.
Sorry again.

[Robert Dodier]

Ticket moved from /p/maxima/bugs/4310/