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This integral is converted to
integrate((1+tan(x+%pi/6)^2)/tan(x+%pi/6),x,0,%pi/6)
Eventually, rischint is called and the error comes from
somewhere in rischint.
(%i1) integrate((tan(x)^2+1)/tan(x),x,%pi/6,%pi/3);
`sign' called on an imaginary argument:
1/4
(- 1)
-- an error. Quitting. To debug this try
debugmode(true);
Right result is log(3).
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user_id=28849
This integral is converted to
integrate((1+tan(x+%pi/6)^2)/tan(x+%pi/6),x,0,%pi/6)
Eventually, rischint is called and the error comes from
somewhere in rischint.
Logged In: YES
user_id=28849
Originator: NO
This no longer produces an error. After asking if sin(x+%pi/6) is positive and if sin(x+%pi/3) is positive (I answered "yes"), maxima says the answer is
log(sqrt(3)/2)+log(4)/2+log(2)+log(3/4)/2
logcontract converts this to log(9)/2, which is log(3).
Closing this bug. Should another bug be opened because maxima asks these questions? The questions come from limit, via sin-cos-intsubs.
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