limit (((1+1/x)^x)*x-e*x, x, inf);
Is e positive, negative or zero?
pos;
Is e - %e positive, negative or zero?
zero;
0
The correct result with these answers is given when %e is substituted for e:
limit(((1+1/x)^x)*x-%e*x,x,inf) => -%e/2
Maxima 5.46.0 SBCL 2.2.5 Windows
Diff: