#363 taylor returns zeroa

closed
nobody
5
2007-09-08
2003-07-19
No

taylor(x/log(x),x,inf,1)

returns (zeroa+1/log(x)+...)*x+...

I believe that 'zeroa' is intended to be strictly internal.
Substituting 0 for zeroa gives the correct result.

Discussion

  • Robert Dodier

    Robert Dodier - 2006-04-09
    • labels: --> Lisp Core - Taylor
     
  • Dan Gildea

    Dan Gildea - 2007-09-08

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    fixed in hayat.lisp rev 1.27

    (%i18) taylor(x/log(x),x,inf,1);
    (%o18) +(+1/log(x))*x

     
  • Dan Gildea

    Dan Gildea - 2007-09-08
    • status: open --> closed
     

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