#3415 limit doesn't check for zero coefficients in limit((a*x+1)/(a*x+2),x,inf)

[Stavros Macrakis]

 limit((a*x+1)/(a*x+2),x,inf) => 1

If a=0, the correct answer is 1/2.

"5.41.0a_dirty"
Maxima build date: "2017-10-24 09:10:17"
Host type: "x86_64-w64-mingw32"
Lisp implementation type: "SBCL"
Lisp implementation version: "1.3.18"

[Stavros Macrakis]

"5.41.0a_dirty"
Maxima build date: "2017-10-24 09:10:17"
Host type: "x86_64-w64-mingw32"
Lisp implementation type: "SBCL"
Lisp implementation version: "1.3.18"

[Barton Willis]

When a is declared to be zero, this is fixed by Commit [37f222]. But when a hasn't been declared to be zero, we still have limit((a*x+1)/(a*x+2),x,inf) => 1

Arguably there is still a bug here, but I would say that limit((a*x+1)/(a*x+2),x,inf) => 1 is consistent with the rest of Maxima; for example `integrate(sin(a*x),x) = ...'