Why do you want simp=false? Almost nothing works with simp set to false.
INPUT
build_info();
radcan((6^(log(12)/log(6))+1)^(1/2)), simp=false;
INPUT AND OUTPUT
(%i1) build_info();
(%o1)
Maxima version: "5.28.0-2"
Maxima build date: "2012-08-27 23:16:48"
Host type: "i686-pc-mingw32"
Lisp implementation type: "GNU Common Lisp (GCL)"
Lisp implementation version: "GCL 2.6.8"
(%i2) radcan((6^(log(12)/log(6))+1)^(1/2)), simp=false;
<ABORT>
Why do you want simp=false? Almost nothing works with simp set to false.
Exactly, it is almost an "almost nothing" case.
If there were no ^(1/2) then simp=false would be very beneficial:
(%i1) radcan(6^(log(12)/log(6)));
(%o1) %e^((log(3)^2+2*log(2)^2)/(log(3)+log(2)))*2^(3*log(3)/(log(3)+log(2)))
(%i2) radcan(6^(log(12)/log(6))), simp=false;
(%o2) 12
Setting logsimp=false works around the problem:
(%i3) radcan((6^(log(12)/log(6))+1)^(1/2)), logsimp=false;
(%o3) %e^(log(%e^(log(3)+2*log(2))+1)/2)
Thereafter, one needs to call radcan repeatedly:
(%i4) radcan(%);
(%o4) sqrt(13)
Anyway, I think that specifying simp=false should not cause a fatal error.
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