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Maxima version: 5.26.0
Lisp: GNU Common Lisp (GCL) GCL 2.6.8 (a.k.a. GCL)
After replace %i to polarform(%i) or domain:complex; we get correct result:
Other example: integrate(exp(x^5),x,0,1)
(%i9) assume(k>1)$ declare(k,odd)$
"Is "(k-1)/k" an "integer"?"n;
(%i15) quad_qags(exp(x^5), x, 0, 1);
Thank you kindly for the detailed answer.
I seem to recall reading that maxima uses complex numbers by default. As a general comment I find it odd that polarform(%i) would not give the same result as just %i.
However I've learned something. Much appreciated.
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@@ -1,4 +1,3 @@
Observed behavior is to be expected given the current assumptions about simplification of complex numbers. Marking this report "closed" accordingly.
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