#2274 Taylor of nested log expression

[Barton Willis]

(%i131) log(log(x))^5/log(x)^5;
(%o131) log(log(x))^5/log(x)^5
(%i132) taylor(%,x,1,3);

(%o132)/T/ (mplus()+...)/(x-1)^5+(mplus()+...)/(x-1)^4+(mplus()+...)/(x-1)^3+(mplus()+...)/(x-1)^2+(mplus()+...)/(x-1)+(mplus()+...)*(x-1)+(mplus()+...)*(x-1)^2+(mplus()+...)*(x-1)^3+...

I think that log(x-1)^5/(x-1)^5 + ... is a better answer. Simplifying %o32 yields 0. And that's not a good answer.