(%i1) integrate(1/(a^2-x^2), x);
Maxima version: 5.16.3Maxima build date: 22:48 8/24/2008host type: i686-pc-mingw32
Maxima's answer might not be what you want, but it's correct. Where defined,
the functions log(x-a) and log(a-x) differ by a constant. Checking Maxima's answer,
(%i21) integrate(1/(a^2-x^2), x);
Maybe you would like to use logabs : true
(%i23) integrate(1/(a^2-x^2), x), logabs;
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