From: Benjamin Root <ben.root@ou...>  20110105 01:30:13

On Tue, Jan 4, 2011 at 6:17 PM, Paul Ivanov <pivanov314@...> wrote: > Gf B, on 20110104 12:31, wrote: > > On Mon, Jan 3, 2011 at 3:53 PM, Paul Ivanov <pivanov314@...> > wrote: > > Gf B, on 20110103 15:23, wrote: > > > > Can such a "grid of grids" be done with matplotlib? If so, could > someone > > > > show me how? > > > > > > You'll be able to group the inner grids visually by adjusting the > > > spacing. As far as getting the spines to only outline the outer > > > grid, and not the inner grid  I think you'll have to do it > > > manually by hiding the appropriate spines for the inner subplots. > > > > > > > This sort of adhoc manual tweaking is what I was hoping to avoid. > > > > What would it take to implement a "true" gridofgrids function in > > matplotlib? What I mean by this is a function that can arrange in a grid > > not only plots but also other grids. (Is this a question for the devel > > group?) > > I think the true gridofgrids functunality is already > implemented. Here's a replication of your Mathematica plots: > >  > import numpy as np > import matplotlib.pyplot as plt > import matplotlib.gridspec as gridspec > from itertools import product > > def squiggle_xy(a, b, c, d, i=np.linspace(0.0, 2*np.pi, 200)): > return np.sin(i*a)*np.cos(i*b), np.sin(i*c)*np.cos(i*d) > > f = plt.figure(figsize=(8, 8)) > > # gridspec inside gridspec > outer_grid = gridspec.GridSpec(4, 4, wspace=0.0, hspace=0.0) > for i in xrange(16): > inner_grid = gridspec.GridSpecFromSubplotSpec(3, 3, > subplot_spec=outer_grid[i], wspace=0.0, hspace=0.0) > a, b = int(i/4)+1,i%4+1 > for j, (c, d) in enumerate(product(range(1, 4), repeat=2)): > ax = plt.Subplot(f, inner_grid[j]) > ax.plot(*squiggle_xy(a, b, c, d)) > ax.set_xticks([]) > ax.set_yticks([]) > f.add_subplot(ax) > > all_axes = f.get_axes() > > #show only the outside spines > for ax in all_axes: > for sp in ax.spines.values(): > sp.set_visible(False) > if ax.is_first_row(): > ax.spines['top'].set_visible(True) > if ax.is_last_row(): > ax.spines['bottom'].set_visible(True) > if ax.is_first_col(): > ax.spines['left'].set_visible(True) > if ax.is_last_col(): > ax.spines['right'].set_visible(True) > > plt.show() >  > > It's a matter of taste, but I think you can get away hiding all > spines, and just setting the hspace and wspace for the outer_grid > to some small value (this is what I meant by 'adjusting the > spacing'). > > I'll send a patch to the devel list shortly adding this example > with the following documentation > > A Complex Nested GridSpec using SubplotSpec > =========================================== > Here's a more sophisticated example of nested gridspect where we put > a box around outer 4x4 grid, by hiding appropriate spines in each of the > inner 3x3 grids. > > it'll be placed on the gridspec page, after this section: > > http://matplotlib.sourceforge.net/users/gridspec.html#gridspecusingsubplotspec > > best, >  > Paul Ivanov > 314 address only used for lists, offlist direct email at: > http://pirsquared.org  GPG/PGP key id: 0x0F3E28F7 > > Just to add, because it is related, another tool that gives you advanced control over your axes is the AxesGrid toolkit: http://matplotlib.sourceforge.net/mpl_toolkits/axes_grid/index.html#toolkitaxesgridindex However, gridspec should be exactly what you need for this particular problem. Ben Root 