Hi,
As far as I know, the destination coordinate of trans* is a display
(canvas) coordinate, not the normalized figure coordinate. It has a
dimension of f.get_figwidth()*f.get_dpi(),
f.get_figheight()*f.get_dpi().
For example, transFigure transforms the normalized figure coordinate
to the display coordinate.
See if something like below works for you.
ax = gca()
f = gcf()
x1, y1, x2, y2 = 0.2, 0.3, 0.4, 0.5
trans = ax.transData + f.transFigure.inverted()
ax_x1, ax_y1 = trans.transform_point([x1, y1])
ax_x2, ax_y2 = trans.transform_point([x2, y2])
ax_dx, ax_dy = ax_x2  ax_x1, ax_y2  ax_y1
a = axes([ax_x1, ax_y1,ax_dx, ax_dy])
IHTH,
JJ
On Mon, Sep 29, 2008 at 8:10 AM, Yves Revaz <yves.revaz@...> wrote:
> Dear List,
>
> I would like to define a new second plot inside a first plot using the
> axes command.
> But I need the position and size do be defined not by the relative
> figure coordinates
> but by data coordinates.
>
> I have found the following trick :
>
> ax = gca()
> f = gcf()
> x,y = ax.transData.transform([x,y])/f.transFigure.transform([1,1])
> a = axes([x,y,dy,dy])
>
> However, if the position is now ok, the size (dx,dy) is still on
> relative figure coordiate.
> Ok, I could think a bit more and find how its possible to transform it,
> but I would
> like to ask the list if there is an easier way to do that.
>
> By the way, why do I have to divide by f.transFigure.transform([1,1]) ?
> I expected that ax.transData.transform did return already normalized
> values.
>
>
> Thanks in advance.
>
> yves
>
>
>
> 
> (o o)
> oOO(_)OOo
> Yves Revaz
> Laboratory of Astrophysics EPFL
> Observatoire de Sauverny Tel : ++ 41 22 379 24 28
> 51. Ch. des Maillettes Fax : ++ 41 22 379 22 05
> 1290 Sauverny email : Yves.Revaz@...
> SWITZERLAND Web : http://www.lunix.ch/revaz/
> 
>
>
> 
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