[Matplotlib-users] polar() is not equal to ax.plot (where ax is a PolarAxes)? From: plaf - 2009-08-03 02:19:38 ```Hi all, I have been trying both ways of plotting polar and found that they behave differently? Is it just me? I have sets of theta and R to plot, and when I plotted in console using polar() it produces different plot (!) than when I used ax.plot() from my application. I compared this with the plot produced in Matlab using the same sets of data, and found that it looked closer to my plot produced using polar(). I am confused :( Thank you -- View this message in context: http://www.nabble.com/polar%28%29-is-not-equal-to-ax.plot-%28where-ax-is-a-PolarAxes%29--tp24784409p24784409.html Sent from the matplotlib - users mailing list archive at Nabble.com. ```
 Re: [Matplotlib-users] polar() is not equal to ax.plot (where ax is a PolarAxes)? From: Michael Droettboom - 2009-08-03 13:16:31 ```I'm not able to see a difference between the two methods here: from pylab import * import numpy as np r = np.arange(0, 3.0, 0.01) theta = 2*np.pi*r fig = figure() ax = fig.add_axes([0.1, 0.1, 0.8, 0.8], polar=True) ax.plot(theta, r) show() polar(theta, r) show() Can you provide a standalone script that demonstrates the difference? What version of matplotlib are you using? Cheers, Mike plaf wrote: > Hi all, > > I have been trying both ways of plotting polar and found that they behave > differently? > Is it just me? > > I have sets of theta and R to plot, and when I plotted in console using > polar() it produces different plot (!) than when I used ax.plot() from my > application. I compared this with the plot produced in Matlab using the same > sets of data, and found that it looked closer to my plot produced using > polar(). > > I am confused :( > > Thank you > -- Michael Droettboom Science Software Branch Operations and Engineering Division Space Telescope Science Institute Operated by AURA for NASA ```