That is very cool, I hadn't thought of it!
So what you're saying is that any transformation (a complex distortion) of a regular rectangular grid is fine. The fact that the grid's 'pixels' are four sided quadrilaterals satisfies this condition and the contour algorithm works...

>>> "Mark Bakker" <> 7/11/2007 11:36 >>>
Viraj and Jeff -

Maybe one extension of Jeff's answer.
The process works as long as x, y, and z are 2D arrays of the same size and shape.
Hence, x and y don't have to form a rectangular grid.
I have used this feature regularly for conformal mapping.
And it makes a lot of sense.
The contour routine simply looks for intersections between x and y values.
Then when it plots it uses the x and y values in the arrays.
So when those are not a rectangular grid, it doesn't care.
It's a cool feature.
I can give an example if you want,



Viraj Vajratkar wrote:
> hey guys... i got it... u can use contour(x,y,z)... as in
> x=load('urfile1.dat'), y=load('urfile2.dat), z=load('urfile3.dat
> ').... and then type out the above.... for details about the
> parameters x,y,z see... .
> .... so
> matplotlib CAN plot a contour from discrete points!!!.... ive tried it
> and it works...
Viraj:  That only works because x and y describe a rectangular grid.  If
x and y described irregularly spaced points, you would need to grid the
data first using one of the methods described on that Cookbook page.


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