From: Uwe B. <ou...@ma...> - 2018-02-03 15:29:16
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Hi I swore this worked till recently: I have k=1:N+1 x(k+1)=x(k)+h; y(k+1)=f(x(k+1)); z(k+1)=g(x(k+1)); end So I mark it and run indent-region And I receive for k=1:N+1 x(k+1)=x(k)+h; y(k+1)=f(x(k+1)); z(k+1)=g(x(k+1)); end Which is absurd, I should have obtained for k=1:N+1 x(k+1)=x(k)+h; y(k+1)=f(x(k+1)); z(k+1)=g(x(k+1)); end Now I run matlab-indent-sexp And obtain again for k=1:N+1 x(k+1)=x(k)+h; y(k+1)=f(x(k+1)); z(k+1)=g(x(k+1)); end What is up here? Or is the culprit GNU emacs 27? Uwe Brauer |