[Marathonman-devel] ScriptException in Main Window

[Vamsee <kri...@ya...>]

Hi All,
   
  I encountered a Script Exception: NameError: default File "", line 1, in? when i tried to record the test.
  I found the similar posting in forum ( https://sourceforge.net/forum/forum.php?thread_id=1174056&forum_id=152821 ), but that is solving in case the Fixture is not generated.
   
   
  Here is the problem description:
   
  When i tried to record Java application the error ScriptException: NameError: default File "", line 1, in?" appears. 
  When test is done it launched the application successfully.
  Iam also able to test & record the SampleAppDemo successfully.
  I also tried by including the line marathon.runtime.port=2222 at the end in .mpf file ,it  gave same error when tried to record.
   
  Marathon version:marathon-0.90a
  Java version:jre1.5.0
   
  Description: 
  Method to launch application:"C:\Program Files\Application\Console\Jre\bin\javaw.exe"  -cp ..\config;console.jar gui/MainClass
   
  Method of configuration in marathon
   
   In create and manage configuration window i gave some name (test) & selected directory as c:/Program files/Application folder.
  Description, resolvers & properties fields are empty.
   
  In Main tab for Mainclass i have given main class of application as gui/MainClass & rest all fields are empty.
   
  In classpath tab I have added all the jars & clicked at test it launched the application successfully then i saved it with same name as test in the same c:/Program files/Application path.
   
  Then selected the above saved .mpf file & clicked OK, marathon window opened.when  i clicked Record button a popup showed ScriptException: NameError: default File "", line 1, in?" .
   
  The default fixture was generated as follows
   
  import gui/MainClass
   
  class Fixture:
              def start_application(self):
                          args = []
                          gui/MainClass.main(args)
   
              def teardown(self):
                          pass
   
              def setup(self):
                          self.start_application()
   
  Please reply ASAP. This is really urgent.
   
  Thanks in advance
  --Vamsee
   

		
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