Re: [Linuxcommand-discuss] shell printf function

[Bram M. <bra...@li...>]

On Sun, 2003-02-16 at 03:30, William Shotts wrote:
> Bram Mertens wrote:
[snip]
> > ---sig-general---
> > #!/bin/bash
> > current_uptime=$(uptime)
> > current_kernel=$(uname -r)
> > current_machine=$(uname -m)
> > current_release="SuSE 8.1 Pro"
> > 
> > echo -n '# '; echo -n $current_release; echo -n ' kernel '; echo -n
> > $current_kernel; echo -n ' '; echo -n $current_machine; echo ' 128MB RAM
> > #'
> > echo -n '#  '; echo -n $current_uptime; echo ' #'
> > echo '</pre>'
> > ---end---
[snip]
> bash contains a printf command that is mostly like the C/perl/etc 
> function.  Try "help printf" at the bash prompt.  Failing that, many 
> distributions have a printf program that can be called from scripts. 
> Try "man printf"

I can't seem to get this working, I've tried several variations of the
following but A always get the same error:
m8ram@linux:~> sig-general
# SuSE 8.1 Pro kernel 2.4.19-4GB i686 128MB RAM #
#  7:59pm up 11 days, 1:21, 6 users, load average: 2.18, 2.13, 2.10 #
/home/m8ram/bin/sig-general: line 9: syntax error near unexpected token
`"# %-65s #",'
/home/m8ram/bin/sig-general: line 9: `printf("# %-65s #",
curent_uptime)'

I've tried to specify the variable as $current_uptime,
$(surrent_uptime), ($current_uptime),...
I've tried %c and %s, single quotes, double quotes...

What is the right format?

TIA
-- 
#  Mertens Bram "M8ram" <bra...@li...>   Linux User #249103  #
# SuSE 8.1 Pro kernel 2.4.19-4GB i686 128MB RAM #
#  8:01pm up 11 days, 1:23, 6 users, load average: 2.59, 2.22, 2.13 #