Re: [Linux-fbdev-users] Question on time system

[Yoder, J. <Joh...@am...>]

I think you're reinventing the wheel here. All that is needed to get the
date in that format is `/bin/date +%Y%m%d%H%M%S` which works on most
*nix systems. All you are doing the "+%Y"... is just reformatting the
output of the date command.

=20

Regards,

=20

John Yoder

=20

________________________________

From: lin...@li...
[mailto:lin...@li...] On Behalf Of
Bui Sy Phong
Sent: Tuesday, September 19, 2006 8:49 AM
To: lin...@li...
Subject: [Linux-fbdev-users] Question on time system

=20

Hi everybody,

I know that i post this question in a wrong place, but if someone can
help me to resolve it, it will be wonderful for me.

In fact, i must write a little program wich diplay the local time of
system on this format (a string) : Year/Mount/Day/Hour/Minute/Second ,
like : 20060919164421=20

So, i can get the number of second since : 01/01/1970 at 00:00:00 but i
dont know how to convert this to a string like above.

Here's my little code to get the number of second since 01/01/1970 :

#include < stdio.h>
#include <time.h>
#include <stdint.h>


int main(void)
{
    system("date");
    printf("\n");
    time_t result;
    result =3D time(NULL);
    printf("%s%ju secs since January 1, 1970 0:00 UTC\n",=20
        asctime(localtime(&result)),
            (uintmax_t)result);
    unsigned int seconds =3D (uintmax_t)result;
    printf("%u\n", seconds);
    return(0);

   =20
}

I know that i must use strftime() to convert but i dont know how.=20

So, i post this question here. And waiting for your helpful.

Thanks very much.

P/S : I dont care about Timezone (it's always in UTC - GMT)