I think you're reinventing the wheel here. All that is needed to get the
date in that format is `/bin/date +%Y%m%d%H%M%S` which works on most
*nix systems. All you are doing the "+%Y"... is just reformatting the
output of the date command.
=20
Regards,
=20
John Yoder
=20
________________________________
From: lin...@li...
[mailto:lin...@li...] On Behalf Of
Bui Sy Phong
Sent: Tuesday, September 19, 2006 8:49 AM
To: lin...@li...
Subject: [Linux-fbdev-users] Question on time system
=20
Hi everybody,
I know that i post this question in a wrong place, but if someone can
help me to resolve it, it will be wonderful for me.
In fact, i must write a little program wich diplay the local time of
system on this format (a string) : Year/Mount/Day/Hour/Minute/Second ,
like : 20060919164421=20
So, i can get the number of second since : 01/01/1970 at 00:00:00 but i
dont know how to convert this to a string like above.
Here's my little code to get the number of second since 01/01/1970 :
#include < stdio.h>
#include <time.h>
#include <stdint.h>
int main(void)
{
system("date");
printf("\n");
time_t result;
result =3D time(NULL);
printf("%s%ju secs since January 1, 1970 0:00 UTC\n",=20
asctime(localtime(&result)),
(uintmax_t)result);
unsigned int seconds =3D (uintmax_t)result;
printf("%u\n", seconds);
return(0);
=20
}
I know that i must use strftime() to convert but i dont know how.=20
So, i post this question here. And waiting for your helpful.
Thanks very much.
P/S : I dont care about Timezone (it's always in UTC - GMT)
|