From: Roy S. <roy...@ic...> - 2018-03-20 18:51:54
|
On Tue, 20 Mar 2018, David Knezevic wrote: > IIRC we stick them at the end, so typically the last (i.e. (rank-1)^th) > processor will own all the SCALARs. This is correct, but please try to avoid writing codes depending on it; it's one of the upcoming items on our "Stuff I thought would be fine because small N but which I need to change because INL Ns are huge" chopping block list (where in this case N is the number of SCALAR dofs in a problem). --- Roy |