Re: [Jsynthlib-devel] Question for Hex/Bin wizards

[Steven S. <ste...@co...>]

Joe Emenaker wrote:

> Steven Schmidt wrote:
>
>> Given the following specification, what value would you find in the 
>> two bytes 230 and 231  for HI SAMPLE NO: 306 (decimal)?
>> 230 - bit 7  HI START OFFSET  0:OFF, 1:ON
>> 230 - bit 6 HI REVERSE 0:OFF, 1:ON
>> 230 - bit 0-6  HI SAMPLE NO.(MSB) 00~~03E7 : 00~~999
>> 231  HI SAMPLE NO.(LSB)
>
>
> 306 decimal is binary 100110010
>
> I don't know what your HI START OFFSET and HI REVERSE bits are 
> supposed to be. 

sadly, neither do I.

> Also, the spec makes reference to a bit #7 *and* a bit #0, which makes 
> me think that your patch data uses 8-bit bytes. If that true, then 
> your bits arrange themselves as: 

I thought it odd that the spec referred to both bit 6 *and* bits 0-6 for 
the same byte, but that is what it said.  This thing must have been 
updated since the spec that Korg put on its web site, because I would 
expect to find a 0x32 sitting next to a 0x?1 or 0x?2, but this is not 
the case, so - back to the drawing board, or debugger.  Thanks for doing 
the math Joe - I'm still confused but at least I have an idea where I'm 
going.
-Steve