Re: [Jsynthlib-devel] Question for Hex/Bin wizards

[Joe E. <jo...@em...>]

Steven Schmidt wrote:

> Given the following specification, what value would you find in the 
> two bytes 230 and 231  for HI SAMPLE NO: 306 (decimal)?
> 230 - bit 7  HI START OFFSET  0:OFF, 1:ON
> 230 - bit 6 HI REVERSE 0:OFF, 1:ON
> 230 - bit 0-6  HI SAMPLE NO.(MSB) 00~~03E7 : 00~~999
> 231  HI SAMPLE NO.(LSB)

306 decimal is binary 100110010

I don't know what your HI START OFFSET and HI REVERSE bits are supposed 
to be. Also, the spec makes reference to a bit #7 *and* a bit #0, which 
makes me think that your patch data uses 8-bit bytes. If that true, then 
your bits arrange themselves as:

   ??000001 00110010

Which is 0x?1 0x32

If you made an error when copying the spec to your e-mail... and your 
patch data is actually in 7-bit bytes, then the bits are:

  ??00010 0110010

which would be 0x?2 0x32

- Joe