Joe Emenaker wrote:
> Steven Schmidt wrote:
>
>> Given the following specification, what value would you find in the
>> two bytes 230 and 231 for HI SAMPLE NO: 306 (decimal)?
>> 230 - bit 7 HI START OFFSET 0:OFF, 1:ON
>> 230 - bit 6 HI REVERSE 0:OFF, 1:ON
>> 230 - bit 0-6 HI SAMPLE NO.(MSB) 00~~03E7 : 00~~999
>> 231 HI SAMPLE NO.(LSB)
>
>
> 306 decimal is binary 100110010
>
> I don't know what your HI START OFFSET and HI REVERSE bits are
> supposed to be.
sadly, neither do I.
> Also, the spec makes reference to a bit #7 *and* a bit #0, which makes
> me think that your patch data uses 8-bit bytes. If that true, then
> your bits arrange themselves as:
I thought it odd that the spec referred to both bit 6 *and* bits 0-6 for
the same byte, but that is what it said. This thing must have been
updated since the spec that Korg put on its web site, because I would
expect to find a 0x32 sitting next to a 0x?1 or 0x?2, but this is not
the case, so - back to the drawing board, or debugger. Thanks for doing
the math Joe - I'm still confused but at least I have an idea where I'm
going.
-Steve
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