StringValue and escape

[Patrick Dowler]

In some code, I am trying to construct a new StringValue, eg

  StringValue sv = new StringValue("abcd");

When I write out the results (via SelectDeparser or just looking at the value returned from sv.getValue() or sv.getNonEscapedValue() the first and last letters are missing. Is this thing parsing a string literal? That is, do I need to include single or double quote characters, in addition to the string, eg

  StringValue sv = new StringValue("'abcd'");

This works, but I want to know if it is on purpose or if I am not understanding it as it doesn't quite make sense to me.

thanks,

Patrick

[Leonardo Francalanci]

Yes, that's how is supposed to work: the parser calls the constructor with the "escapedValue":

public StringValue(String escapedValue)

so it calls it with, say, "'mystring'"