Re: [json-lib-user] Square brackets in strings

[Andres A. <aal...@ya...>]

Hi Elizabeth,=0A=0AAnother user also registered this issue in the bug datab=
ase,=0Ahttp://sourceforge.net/tracker/index.php?func=3Ddetail&aid=3D1650535=
&group_id=3D171425&atid=3D857928=0AI'm currently looking at it, I'll see wh=
at I can do :-)=0A=0ARegards,=0AAndres=0A =0A------------------------------=
-------------=0Ahttp://jroller.com/page/aalmiray=0A--=0AWhat goes up, must =
come down. Ask any system administrator.=0AThere are 10 types of people in =
the world: Those who understand binary, and those who don't.=0ATo understan=
d recursion, we must first understand recursion.=0A=0A----- Mensaje origina=
l ----=0ADe: Elizabeth Keogh <ek...@th...>=0APara: json-lib-use=
r...@li...=0AEnviado: jueves, 1 de febrero, 2007 10:01:34=0AAs=
unto: [json-lib-user] Square brackets in strings=0A=0ADear Json-lib devs,=
=0A=0AThank you for your library! It's served us very well for the past few=
 months.=0A=0AUnfortunately my customers have started putting square bracke=
ts just like the example below=0Ain the text they're sending us, with the e=
xception that results (from info3).=0A=0A=0A    public void testThatJsonIsN=
otConfusedBySquareBrackets() {=0A        HashMap<String, String> map =3D ne=
w HashMap<String, String>();=0A        map.put("address", "1 The flats [Upp=
er floor]");=0A        map.put("phoneNumber", "[+44] 582 401923");=0A      =
  map.put("info1", "[Likes coffee]");=0A        map.put("info2", "[Likes co=
ffee] [Likes tea]");=0A        map.put("info3", "[Likes coffee [but not wit=
h sugar]]");=0A        =0A        JSONObject json =3D JSONObject.fromObject=
(map);=0A    }=0A=0A Due to the intrigues of multiple departments all using=
 this data, there's little to no chance of stopping them.=0A=0A=0A=0ACan yo=
u help?=0A=0AThe problem seems as though it might be here, in JSONUtils:=0A=
=0A   public static boolean mayBeJSON( String string )=0A   {=0A      retur=
n string !=3D null=0A            && ("null".equalsIgnoreCase( string )=0A  =
                || (string.startsWith( "[" ) && string.endsWith( "]" )) || =
(string.startsWith( "{" ) && string.endsWith( "}" )));=0A   }=0A=0AIs there=
 any chance please of fixing this, eg: by replacing the above with a regula=
r expression that checks the String is truly JSON?=0A=0AMany thanks,=0ALiz.=
=0A=0A--=0AElizabeth Keo...@th...=0Ahttp://www.livejournal.=
com/users/sirenian=0A=0A=0A=0A---------------------------------------------=
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