Re: [jCharts-users] Simple JChart question

[Nathaniel G. A. <nat...@ya...>]

you have to add the other datapoints to the chart, as in:


scatterPlotDataSet.addDataPoints( points, Color.red, "Proprietary" );
scatterPlotDataSet.addDataPoints( points2, Color.red, "Proprietary" );


--- "Arcadius A." <ah...@sh...> wrote:
> Hello!
> I'm new to JCharts.
> I'm trying to modify the "ScatterPlotChartServlet" example to do what I 
> need.
> 
> The actual code in "ScatterPlotChartServlet" looks like the following:
> 
>   private ScatterPlotDataSet createScatterPlotDataSet() {
>       Point2D.Double[] points = new Point2D.Double[ 20 ];
>       Point2D.Double[] points2 = new Point2D.Double[ 20 ];
>       for( int x = 0; x < 20; x++ ) {
>           //--- y = x2
>           points[ x ] = ScatterPlotDataSet.createPoint2DDouble();
>           points[ x ].setLocation( x, Math.pow(x,2 ) );        }
>       ScatterPlotDataSet scatterPlotDataSet = new ScatterPlotDataSet( 
> this.createScatterPlotProperties() );
>       scatterPlotDataSet.addDataPoints( points, Color.red, "Proprietary" );
>       return scatterPlotDataSet;
>   }
> 
>    Me, I'd like to draw 3 graphs, for instance  :
> y=Math.pow(x,2)
> y=Math.pow(x,3)
> y=Math.sin(Math.PI*x)
> 
> on the SAME chart.
> 
> My question is: How can I modify the code of the 
> "ScatterPlotChartServlet" above to have 3 graphs on the SAME chart?
> creating two others points2[] and points3[]  objects for the 2 remaining 
> graphs did not help.
> 
> Thanks.
> 
> AA.
> 
> 
> 
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