Help -- It++ in windows

[wavestar]

Hi, I have succeed compile the it++ in window. I comiled it in viusal C++ express.
Now I try to test the itpp.lib -- the libary file in visual C++ 6.0.
I have set the lib, include directory.
My test cpp file is :

include <itpp/itcomm.h>

using namespace std;
using namespace itpp;

void main()
{

ivec a("0 0.7 5 9.3");

int b = a(5);

}

comiled error:
--------------------Configuration: Test - Win32 Debug--------------------
Compiling...
test.cpp
c:\itpp-4.0.1\itpp\base\math\misc.h(102) : error C2995: '<<' : template function has already been defined
c:\program files\microsoft visual studio\vc98\include\complex(345) : see declaration of '<<'
c:\itpp-4.0.1\itpp\base\math\misc.h(140) : error C2995: '>>' : template function has already been defined
c:\program files\microsoft visual studio\vc98\include\complex(326) : see declaration of '>>'
c:\itpp-4.0.1\itpp\base\mat.h(316) : error C2143: syntax error : missing ';' before '<'
c:\itpp-4.0.1\itpp\base\mat.h(441) : see reference to class template instantiation 'itpp::Mat<Num_T>' being compiled
c:\itpp-4.0.1\itpp\base\mat.h(316) : fatal error C1903: unable to recover from previous error(s); stopping compilation
c:\itpp-4.0.1\itpp\base\mat.h(441) : see reference to class template instantiation 'itpp::Mat<Num_T>' being compiled
Error executing cl.exe.

test.obj - 4 error(s), 0 warning(s)

---

the function in trouble:
namespace std {

//! \cond

ifndef HAVE_STD_ISINF

if (HAVE_DECL_ISINF == 1) || defined(HAVE_ISINF)

inline int isinf(double x) { return ::isinf(x); }

elif defined(FPCLASS)

inline int isinf(double x)
{
if (::fpclass(a) == FP_NINF) return -1;
else if (::fpclass(a) == FP_PINF) return 1;
else return 0;
}

else

inline int isinf(double x)
{
if ((x == x) && ((x - x) != 0.0)) return (x < 0.0 ? -1 : 1);
else return 0;
}

endif // #if (HAVE_DECL_ISINF == 1) || defined(HAVE_ISINF)

define HAVE_STD_ISINF 1

endif // #ifndef HAVE_STD_ISINF

ifndef HAVE_STD_ISNAN

if (HAVE_DECL_ISNAN == 1) || defined(HAVE_ISNAN)

inline int isnan(double x) { return ::isnan(x); }

else

inline int isnan(double x) { return ((x != x) ? 1 : 0); }

endif // #if (HAVE_DECL_ISNAN == 1) || defined(HAVE_ISNAN)

define HAVE_STD_ISNAN 1

endif // #ifndef HAVE_STD_ISNAN

ifndef HAVE_STD_ISFINITE

if (HAVE_DECL_ISFINITE == 1) || defined(HAVE_ISFINITE)

inline int isfinite(double x) { return ::isfinite(x); }

elif defined(HAVE_FINITE)

inline int isfinite(double x) { return ::finite(x); }

else

inline int isfinite(double x)
{
return ((!std::isnan(x) && !std::isinf(x)) ? 1 : 0);
}

endif // #if (HAVE_DECL_ISFINITE == 1) || defined(HAVE_ISFINITE)

define HAVE_STD_ISFINITE 1

endif // #ifndef HAVE_STD_ISFINITE

//! \endcond

//! Output stream operator for complex numbers
template <class T>
std::ostream& operator<<(std::ostream &os, const std::complex<T> &x)
{
os << x.real();
ios::fmtflags saved_format = os.setf(ios::showpos);
os << x.imag();
os.setf(saved_format, ios::showpos);
return os << 'i';
}

//! Input stream operator for complex numbers
template <class T>
std::istream& operator>>(std::istream &is, std::complex<T> &x)
{
T re, im;
char c;
is >> c;
if (c == '(') {
is >> re >> c;
if (c == ',') {
is >> im >> c;
if (c == ')') {
x = complex<T>(re, im);
} else {
is.setstate(ios_base::failbit);
}
} else if (c == ')') {
x = complex<T>(re, T(0));
} else {
is.setstate(ios_base::failbit);
}
} else {
is.putback(c);
is >> re;
if (!is.eof() && ((c = is.peek()) == '+' || c == '-')) {
is >> im >> c;
if (c == 'i') {
x = complex<T>(re, im);
} else {
is.setstate(ios_base::failbit);
}
} else {
x = complex<T>(re, T(0));
}
}
return is;
}

} // namespace std

friend const Mat<Num_T> concat_horizontal <>(const Mat<Num_T> &m1, const Mat<Num_T> &m2);

Anyone can tell me how to fix it? I have struggle for it several days.

Thanks a lot,

[Adam Piątyszek]

Visual C++ 6.0 is not supported for a long time already. Besides, I recommend you to use IT++ with the open-source GCC compilers, preferably on GNU/Linux or any other Unix-like environment.