## Re: [Inkscape-user] shape question

 Re: [Inkscape-user] shape question From: Laszlo - 2005-11-30 10:18:23 ```2005-11-29, k keltez=E9ssel 15.55-kor Patrick Roane ezt =EDrta: > Hey folks, >=20 > I am a fairly new user of Inkscape and was wondering > how I can create a square that has rounded corners on > the top, but streight corners on the bottom? >=20 I have done a little step-by-step tutorial for your question. I did put online: http://khiraly.4242.hu/tmp/roundedRectangle.png Here is in .svg format: http://khiraly.4242.hu/tmp/roundedRectangle.svg So the key steps: Duplicate the rectangle to obtain the same. (Ctrl-D). Convert rectangle into Path. (Ctrl-Shift-C) Best regards,=20 Khiraly ```

 [Inkscape-user] shape question From: Patrick Roane - 2005-11-29 23:55:54 ```Hey folks, I am a fairly new user of Inkscape and was wondering how I can create a square that has rounded corners on the top, but streight corners on the bottom? So far, I've noticed there are only 3 nodes which I can use to modify my square. One of which is used to round the corners- but it does all 4. Is there a way I can only select 2 of the 4 corners to round? Thanks- I hope this makes sense. Patrick ```
 Re: [Inkscape-user] shape question From: Nicu Buculei - 2005-11-30 06:47:37 ```Patrick Roane wrote: > Hey folks, > > I am a fairly new user of Inkscape and was wondering > how I can create a square that has rounded corners on > the top, but streight corners on the bottom? > > > So far, I've noticed there are only 3 nodes which I > can use to modify my square. One of which is used to > round the corners- but it does all 4. Is there a way I > can only select 2 of the 4 corners to round? You can't do that directly. A solution is to use two squares, one with rounded corners and another with straight corners and apply boolean operations (union) to obtain the desired shape (you will have do decrease the height of the second square) -- nicu ```
 Re: [Inkscape-user] shape question From: Josef Vybiral - 2005-11-30 06:48:13 ```-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 On Wed, 30 Nov 2005 00:55:46 +0100, Patrick Roane wrote: > Hey folks, > > I am a fairly new user of Inkscape and was wondering > how I can create a square that has rounded corners on > the top, but streight corners on the bottom? > > So far, I've noticed there are only 3 nodes which I > can use to modify my square. One of which is used to > round the corners- but it does all 4. Is there a way I > can only select 2 of the 4 corners to round? Hi Patrick, there is a way how you can achieve this but you have to create two rectangles (one of them without rounded corners), convert them to a path (Path - Object to Path) and use boolean operation[1] "Difference" to cut off rounded corners of one side. By this you'll get rectangle with only two rounded corners. The disadvantage is that it is no longer a shape but a path, so you can not easily change the radius of rounded corners. best regards Josef [1] Boolean operations: http://tavmjong.free.fr/INKSCAPE/MANUAL/html/ch08s04.html [2] SVG rectangle specification: http://www.w3.org/TR/SVG/shapes.html#RectElement - -- Using Opera's revolutionary e-mail client: http://www.opera.com/mail/ -----BEGIN PGP SIGNATURE----- Version: GnuPG v1.4.3-cvs (MingW32) - WinPT 0.11.1-beta Comment: GnuPT for windows iD8DBQFDjUr848awga6v/9sRAgpDAKCMhj/36wSWjC321q8IUGqMWPpecACcCXK2 MCO10/+GM/No6k9k08aCrYc= =C3br -----END PGP SIGNATURE----- ```
 Re: [Inkscape-user] shape question From: Laszlo - 2005-11-30 10:18:23 ```2005-11-29, k keltez=E9ssel 15.55-kor Patrick Roane ezt =EDrta: > Hey folks, >=20 > I am a fairly new user of Inkscape and was wondering > how I can create a square that has rounded corners on > the top, but streight corners on the bottom? >=20 I have done a little step-by-step tutorial for your question. I did put online: http://khiraly.4242.hu/tmp/roundedRectangle.png Here is in .svg format: http://khiraly.4242.hu/tmp/roundedRectangle.svg So the key steps: Duplicate the rectangle to obtain the same. (Ctrl-D). Convert rectangle into Path. (Ctrl-Shift-C) Best regards,=20 Khiraly ```