Re: [Htmlparser-user] Excluding some tags

[Manish K. <ma...@we...>]

Sorry i modify my question ignore the previous one.

Is there a way to get the <a>s which are not in the <script> tag?

Thanks,
MAnish

On Wed, Nov 17, 2010 at 12:14 PM, Manish Kashyap <ma...@we...>wrote:

> Thanks for the revert Derrick. So, here's the real problem -
> I do want to retain the script tag. At the same time, I want to override
> all the links in the page. The parser doesn't play nice. Consider the
> scenario underneath for an html
>
> <script>
>>  document.write("<a href='/jslink'>JS Link</a>")
>> </script>
>> <a href="/somelink">Some link</a>
>>
>
> To me the string literal inside script tag above is not a link at all.
> However, when I try to fetch all the <a> using the parser it would give me
> both of the above. Is there a way to not get the <a>s which are not in the
> <script> tag?
>
> Thanks
> Manish
>
>
> On Tue, Nov 16, 2010 at 11:39 PM, Derrick Oswald <der...@gm...
> > wrote:
>
>> Although the filter is correct, the tag enclosing the <script> tag is
>> accepted, and with it it's child tags - including the <script> tag.
>> Maybe a way to do it is to override the ScriptTag class with MyScriptTag
>> so that it prints nothing in the toHtml () call.
>> Add the overridden class to the PrototypicalNodeFactory as described
>> here: http://htmlparser.sourceforge.net/faq.html#composite, and then get
>> all tags and print the whole thing with System.out.println (this.parser.parse(null).toHtml
>> ());
>>
>> On Tue, Nov 16, 2010 at 8:19 AM, Manish Kashyap <ma...@we...>wrote:
>>
>>> This indeed is a newbie question. I could not find a work around to
>>> exclude some tags (<script> in my case) while parsing.
>>>
>>> I tried using the NotFilter as underneath, but it didn't work as I got
>>> all the <script> tags in my NodeList -
>>>
>>>> NotFilter noScriptFilter = new NotFilter();
>>>> noScriptFilter.setPredicate(new NodeFilter(){
>>>>   public boolean accept(Node currNode){
>>>>     if(currNode instanceof TagNode){
>>>>
>>>> if(((TagNode)currNode).getRawTagName().equalsIgnoreCase("script")){
>>>>          return true;
>>>>       }
>>>>     }
>>>>     return false;
>>>>   }
>>>> });
>>>> NodeList allNodes = this.parser.parse(noScriptFilter);
>>>>
>>>
>>> Would appreciate if someone can guide me throgh this.
>>>
>>> Thanks
>>> Manish
>>>
>>>
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>>
>>
>> ------------------------------------------------------------------------------
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>> Spend less time writing and  rewriting code and more time creating great
>> experiences on the web. Be a part of the beta today
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>