From: gnome-perl (bugzilla.gnome.o. <bug...@gn...> - 2010-03-19 21:42:00
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https://bugzilla.gnome.org/show_bug.cgi?id=613369 gnome-perl | Gtk2 | unspecified Summary: Menu popup() release position func on call with undef Classification: Bindings Product: gnome-perl Version: unspecified OS/Version: Linux Status: UNCONFIRMED Severity: minor Priority: Normal Component: Gtk2 AssignedTo: gtk...@li... ReportedBy: us...@zi... QAContact: gtk...@li... GNOME target: --- GNOME version: --- Created an attachment (id=156589) View: https://bugzilla.gnome.org/attachment.cgi?id=156589 Review: https://bugzilla.gnome.org/review?bug=613369&attachment=156589 release previous position func on popup(undef) If $menu->popup() is called with undef for its position function I wonder if it can release any previous position function it's holding onto, the same as when a new (not undef) position func is passed in, per attached diff? -- Configure bugmail: https://bugzilla.gnome.org/userprefs.cgi?tab=email ------- You are receiving this mail because: ------- You are the QA contact for the bug. You are the assignee for the bug. |