Re: [Algorithms] How to derive transformation matrices

[Klaus H. <k_h...@os...>]

----- Original Message -----
From: Steve Wood <Ste...@im...>
To: <gda...@li...>
Sent: Tuesday, July 25, 2000 7:58 PM
Subject: RE: [Algorithms] How to derive transformation matrices
>
> uh...no, it's the perpendicular.  Forces parallel to a surface do not
> interact with the surface (actually, there would be no resulting force for
> any actions parallel to a surface) unless the perpendicular force causes
> penetration so the parallel component then has something to "grab onto".

Steve,
I'm not native to the English language, but I think it's possible that you
are confusing "shear" with "sheer"!?

According to my English dictionary, "sheer" can be used as an adverb:
B.1 Completely, absolutely, directly,
B.2 Perpendicularly, very steeply, straight up or down

The English dictionary uses the term "shear" mostly for 'parallel' things,
like:
1. The bar, or either of the two parallel bars, forming the bed of a lathe
2. "shear plane". [Geol.] a boundary surface between bodies of rock or ice
which have experienced relative motion parallel to the surface.
3. and a lot more samples, that include the term "parallel".

Niki