Re: [Algorithms] Converting floats to a specific range

[Richard F. <ra...@gm...>]

I'll let you use the code i coded for this free of charge!

float makeRight( float val, float wrapsize )
{
 val /= wrapsize;
 switch( (int)val )
{
case 0:
 return wrapsize * val;
case 1:
 return wrapsize * (val-1.0f);
case 2:
 return wrapsize * (val-2.0f);
case 3:
 return wrapsize * (val-3.0f);
case -1:
 return wrapsize * (val+1.0f);
case -2:
 return wrapsize * (val+2.0f);
case -3:
 return wrapsize * (val+2.0f);
}
// just in case you haven't written the case for the incoming value:
return 0.0f;
}

On 7 May 2010 12:36, Zafar Qamar <zaf...@co...> wrote:

> Hi,
>
> I'm sure this problem is pretty simple, but here goes...
>
> I have a set of float numbers that I'm trying to auto-wrap within a
> specific range of 0.0 to wrapSize (wrapSize is positive, and not a power of
> 2)
>
> So, if I choose a wrapSize of 1.0 then I want the following to happen when
> I feed in numbers...
>
> -739.8 --> 0.2
> :
> :
> -1.1 --> 0.9
> -1.0 --> 0.0
> -0.9 --> 0.1
> :
> -0.2 --> 0.8
> -0.1 --> 0.9
> 0.0 --> 0.0
> 0.1 --> 0.1
> :
> 0.9 --> 0.9
> 1.0 --> 0.0
> 1.1 --> 0.1
> :
>
> Can anyone think of a bit of maths for this please? Note that it needs to
> work for any positive value of wrapSize (not just 1.0)
>
> Cheers
> Zafar
>
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