Re: [Fxruby-users] FXList#makeItemVisible and ruby threads

[Joel V. <vj...@PA...>]

Joel VanderWerf wrote:
> 
> I'm updating a FXList from a thread, and I'd like to
> always scroll to the last item. This is what I tried:
> 
> require 'fox'
> include Fox
> 
> app = FXApp.new("List", "TEST")
> win = FXMainWindow.new(app, "list")
> list = FXList.new(win, 10)
> Thread.new do
>   20.times do |i|
>     list << i.to_s
> #    sleep 0.1
>     list.makeItemVisible(list.numItems-1) # no effect
>     sleep 0.1
>   end
> end
> win.show
> app.create
> app.run
> 
> As it is, the makeItemVisible has no effect, immediate or delayed. 
> However, if I uncomment the first sleep, it has an immediate effect, as 
> desired.
> 
> Does that make sense?

I guess a better question is, what is happening during that first sleep 
that I could do manually (without sleeping) to ensure that the 
makeItemVisible call has an effect? I've tried recalc, update, flush, 
forceRefresh. Overkill, I know, but all in the name of science...

Actually, I've found that Thread.pass has the same effect as sleeping, 
so I guess I'll just use that.