From: Gabriel J. <gj...@co...> - 2003-06-30 10:51:24
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Hi Calin, Monday, June 30, 2003, 12:48:43 PM, you wrote: CIP> ----- Original Message ----- CIP> From: "Gabriel Juncu" >> So, can anybody tell me how can I get correct arithmetic in Firebird >> on 18 digits without overflow errors? >> CIP> Hmmm, yes. CIP> Use numeric(18,0) as intermediate values then you only get a overflow CIP> if the result realy overflows. CIP> Ex: CIP> CREATE PROCEDURE W_NUMTST (Param1 numeric(18,4), param2 numeric(18,4)) CIP> RETURNS ( CIP> Res NUMERIC(18,4)) CIP> AS CIP> declare variable n1 numeric(18,0); CIP> declare variable n2 numeric(18,0); CIP> declare variable n numeric(18,0); CIP> begin CIP> n1 = param1*10000; CIP> n2 = param2*10000; CIP> n = n1*n2; CIP> res = n/10000; CIP> suspend; CIP> end You hurried a bit. My first example (and problem) was: Param1 = 5655555; Param2 = 32900; Result = Param1 * Param2; so (56555555 * 10000) * (32900 * 10000) gives 20 digits -> and the result really overflows ;-) That is exactly what Firebird does intenally, and again, if it is made on 64 bits it gives numeric overflow (except this time is much easier to understand it ;-) All I am asking here is if the developers think that this is the normal way that numeric multiply shoud behave, so I should abbandon any hope of seeing this corrected (from my point of view) and start to pollute my stored procedures with computing artifices so I can get correct results for a simple multiply operation. Thanks again for your answer, Gabriel |