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bad lattice constant for ZnTe (zincblende)

ekadants
2008-09-16
2013-06-05
  • ekadants

    ekadants - 2008-09-16

    Dear exciting users,

    I am getting quite bad results for LDA lattice constants of ZnTe and CdTe in zincblende structure.  According to the literature, ZnTe/CdTe equilibrium lattice constant is 6.089/6.480 A, respectively.
    For ZnTe, I am getting
    ==> TOTENERGY.5.55 <== -8584.727350 -> 5.87 A
    ==> TOTENERGY.5.60 <== -8584.726842
    ==> TOTENERGY.5.65 <== -8584.725249
    ==> TOTENERGY.5.70 <== -8584.723405
    ==> TOTENERGY.5.75 <== -8584.720192
    ==> TOTENERGY.5.80 <== -8584.717204
    ==> TOTENERGY.5.85 <== -8584.713107
    ==> TOTENERGY.5.90 <== -8584.708778
    ==> TOTENERGY.5.95 <== -8584.703801  -> 6.30 A
    where number at the end of TOTENERGY.* is half of the lattice constant in a.u, for example,
    TOTENERGY.5.55 corresponds to the lattice constant 5.87 A (5.55*2*0.529177). The energies in my calculation decrease
    uniformly...I tried different things - increasing k-point sampling to 10x10x10, increasing rgkmax together with lmax and density cut-off, neglecting the spin-orbital coupling - nothing seems
    to work for me. I do get good normal lattice constants for other semiconductors such as InAs/GaAs. 

    Does anyone knows what's wrong with my calculations? The above energies were
    produced with the following input, 151 version of exciting and default species files
    (3p states of Cd are treated as valence, for example).

    Best regards, Eugene

    export E_EXE=/usr/local/exciting/0.9.151/pgi/goto/bin/exciting
    export OMP_NUM_THREADS=4
    cd /home/ekadants/ZnTe/zincE

    for i in  5.55 5.60 5.65 5.70 5.75 5.80 5.85 5.90 5.95
    do
    cat > exciting.in << EOF
    tasks
    0

    xctype
    3

    spinorb
      .true.

    avec
       $i       $i     0.0
       $i       0.0     $i
       0.0      $i      $i

    sppath
      '/usr/local/exciting/0.9.151/species/'

    atoms
      2                                   : nspecies
      'Zn.in'                             : spfname
      1                                   : natoms
      0.00 0.00 0.00  0.0 0.0 0.0         : atposl, bfcmt
      'Te.in'                             : spfname
      1                                   : natoms
      0.25 0.25 0.25  0.0 0.0 0.0         : atposl, bfcmt

    ngridk
      8 8 8
    EOF
    ${E_EXE} exciting.in
    rm -f -r exciting.in
    mv EIGVAL.OUT EIGVAL.$i
    mv INFO.OUT  INFO.$i
    mv TOTENERGY.OUT TOTENERGY.$i
    mv EVALCORE.OUT  EVALCORE.$i
    mv EFERMI.OUT EFERMI.$i
    rm -f -r *.OUT
    done

     
    • ekadants

      ekadants - 2008-09-16

      I meant Zn 3p states are treated as valence

       
    • ekadants

      ekadants - 2008-09-23

      I am getting a better 6.0 A lattice constant for ZnTe now. To get the lattice consant  right I had to add "d local orbital" to the default  Zn species file. I took -0.35 a.u. from the atomic calculations, what is the proper procedure for choosing
      these energies? 

               2   3                                    : lorbl, lorbord
        0.1500   0  F                             : lorbe0, lorbdm, lorbve
        0.1500   1  F
      -0.35     0  T

       
      • exciting

        exciting - 2008-10-02

        You're quite correct. For this case the semi-core cut-off energy was set too low in the "species" code. I've now set it to -0.35 Ha, which produces the extra local orbital in Zn.in:

           2   3                                    : lorbl, lorbord
          0.1500   0  F                             : lorbe0, lorbdm, lorbve
          0.1500   1  F
        -0.2410   0  T

        Running this with "rgkmax=8.5" gives:

           5.40000000000000       -8584.76625029792    
           5.45000000074506       -8584.76923592724    
           5.50000000149012       -8584.77168046126    
           5.55000000223517       -8584.77342212194    
           5.60000000298023       -8584.77455769550    
           5.65000000372529       -8584.77510727420    
           5.70000000447035       -8584.77526029399    
           5.75000000521541       -8584.77476164859    
           5.80000000596046       -8584.77400402242    
           5.85000000670552       -8584.77276575883    
           5.90000000745058       -8584.77147097164    
           5.95000000819564       -8584.76956206248    
           6.00000000894070       -8584.76728627976    

        i.e. an equilibrium parameter of 6.015 Angstrom.

        Cheers,
        Kay.

         
    • Anton

      Anton - 2008-09-23

      Eugene:
      Zn has a 3d^10 configuration, so d-bands are fully occupied. By default Zn has one local orbital for 3d with enu=0.15 Ha. Seems like this linearization energy is too high. Instead of adding another l.o. you can try to change the enu of existing local orbital from 0.15 to -0.35 Ha. There is no unique procedure of choosing linearization energies, only physical intuition and a bit of street magic ;)

      Anton.

       

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